Return range of numbers according to the division of total numbers by an integer

Question

Given the following situation:

I need to create a function that receives as parameter (int value and int divisor). The idea is popular an array with the TOTAL of the range passed to the function. That I could do. However, I now need to return the range of these values based on the division between the number passed as parameter and the division value. I will illustrate below:

const sort = (totalImage, totalPeople) => {
    let imageList = new Array;
    var result;
    for (let interval = 1; interval <= totalImage; interval++) {
        let intervalValue = parseInt(interval);
        imageList.push(intervalValue);
    }
    result = totalImage / totalPeople;

I tried an approach with the Slice() method, but I was not successful. From now on, I appreciate any cooperation and I hope I have eluded the problem in the best way possible.

Answer 1

Can use .slice() to slice the array according to the number of people (second argument passed to the function) by inserting into a new array the values in each index of that new array. It would be something like the function array_chunk of PHP.

Use the Math.floor() in the division to round down in cases where the division is not exact.

Behold:

const sort = (totalImage, totalPeople) => {
   let imageList = new Array;
   for (let interval = 1; interval <= totalImage; interval++) {
      let intervalValue = parseInt(interval);
      imageList.push(intervalValue);
   }   
   let result = Math.floor(totalImage / totalPeople);

   let sliced = new Array; // cria nova array
   
   for(let x = 0; x < totalImage; x+=result){
      sliced.push(imageList.slice(x, x+result).join()); // aqui fatia e converte em string
   }
   
   return sliced;
}

console.log(sort(20,4));
console.log(sort(20,3));