Read a string with line break

Question

I need to compare two strings to see if they are equal.

One of them is in a vector of struct and was dealt with the fgets, so it’s a line break. The other one is informed by the keyboard.

I wonder if there is any function to read this second struct with line break, so I can compare it to the first.

Answer 1

You can remove the line break in the first string (in a copy if necessary)

fgets(exemplo, sizeof exemplo, stdin); // assume no errors
len = strlen(exemplo);
if ((len > 0) && (exemplo[len - 1] == '\n')) {
    exemplo[--len] = 0; // remove quebra de linha e actualiza len
}

Answer 2

A solution, rather than changing one of the strings and remove line breaks, can go through implementing a comparison your.

An example of this comparison would be (based slightly on this reply):

// Retorna 0 se as strings forem iguais, -1 se forem diferentes
int CompareStrings(char* a, char* b);

int CompareStrings(char* a, char* b)
{
    int indexA, indexB;
    for(indexA = 0, indexB = 0; indexA < strlen(a) || indexB < strlen(b); ++indexA, ++indexB)
    {
        if(a[indexA] == '\n')
        {
            if(++indexA >= strlen(a))
                indexA = strlen(a);
        }

        if(b[indexB] == '\n')
        {
            if(++indexB >= strlen(b))
                indexB = strlen(b);
        }

        if((a[indexA] == '\0' || b[indexB] == '\0') || (a[indexA] != b[indexB]))
            break;
    }

    // Se ambos terminaram, as strings contidas são iguais.
    if( a[indexA] == '\0' && b[indexB] == '\0' )
        return 0;
    else
        return -1;
}

Example in Ideone tested.

Answer 3

You can do strlen(variavel sem \n), then you copy the end of the string to the location of the \n and after that you can compare the strings.