Loop inside loop While PYTHON

Question

I’m making a program that draws a number from 0 to 5 and the user should guess what it is, but he only has 3 attempts. In case the 3 attempts run out and the user does not guess which is the number, then would show a message saying that exceeded the number of attempts and whether wanted to quit or continue playing, the problem is that come have a loop inside the other if the user type "more" the "continue" assumes I want to return the input saying I tried too many times and not the entire code:

import random
import time
from sys import exit
print('-------------------')
print('JOGO DA ADIVINHAÇÃO')
print('-------------------')
time.sleep(2)
print('Vou pensar num número de 0 a 5...')
time. sleep(1)
tentativa=3
num=random.randint(0, 5)
while True:
 n= int(input('Tente adivinhar qual é: '))
 if tentativa >0:
        if num==n:
            print('Você ACERTOU! PARABÉNS!')
            break
        elif num!=n:
                n2=input(f'Você errou, tem {tentativa}...')
                tentativa=tentativa-1
                continue
 elif tentativa==0:
        while True:
         se=input('Você tentou vezes demais e não acertou digite "mais" para jogar novamente ou "sair" para acabar o jogo: ')
         if se=='sair':
             exit()
         elif se=='mais':
             continue
         elif se!='mais' or se!= 'sair':
             print('Não percebi o que quis dizer...')
             time.sleep(2)
             continue 

How do I make the whole code start again?

Answer 1

It’s just a matter of simplifying the problem. You have little code that does a lot, so it will be better to separate the responsibilities.

You can create a function that reads the user’s attempt:

def ler_tentativa() -> int:
    while True:
        try:
            return int(input('Tente advinhar o número: '))
        except ValueError:
            print('Erro! Informe um valor inteiro')

You can create a role that asks the user if he wants to continue playing:

def tentar_de_novo() -> bool:
    while True:
        answer = input('Digite "mais" para tentar novamente ou "sair" para encerrar')
        if answer not in {'sair', 'mais'}:
            print('Erro! Não entendi o que quis dizer')
            continue
        return answer == 'mais'

And, thus, you create a loop that lasts as long as there are attempts and when to close them and the user ask to play again just you increase to 3 the number of attempts:

tentativas = 3
sorteado = 5

while tentativas > 0:
    tentativas -= 1
    tentativa: int = ler_tentativa()

    if tentativa == sorteado:
        print('Parabéns')
        break

    if tentativas == 0 and tentar_de_novo():
        tentativas = 3
else:
    print('Fim')

Answer 2

You can add an "auxiliary" variable to this and place the trial assignment part and a new number inside the Loop, this way:

import random
import time
from sys import exit
print('-------------------')
print('JOGO DA ADIVINHAÇÃO')
print('-------------------')
time.sleep(2)

inicio = True
while True:

    if(inicio): 
        print('Vou pensar num número de 0 a 5...')
        tentativa=3
        num=random.randint(0, 5)
        time. sleep(1)
        n= int(input('Tente adivinhar qual é: '))
        inicio = False

    if tentativa >0:
        if num==n:
            print('Você ACERTOU! PARABÉNS!')
            break
        elif num!=n:
            n2=input(f'Você errou, tem {tentativa}...')
            tentativa=tentativa-1
            continue

    elif tentativa==0:
        while True:
            se=input('Você tentou vezes demais e não acertou digite "mais" para jogar novamente ou "sair" para acabar o jogo: ')
            if se=='sair':
                 exit()
            elif se=='mais':
                inicio = True
                break
            elif se!='mais' or se!= 'sair':
                print('Não percebi o que quis dizer...')
                time.sleep(2)
                continue

However the code is a little verbose, and apparently with some messages that may cause problem.

I advise to give a studied in functions to make your code less verbose, as some have already mentioned in the answers.