SED USE WITH A VARIABLE

Question

I need to configure two files. sh, the first sshpasssrv.sh file will be responsible for filling in the second file that will be sshpass.sh, the first file when executed, will ask for the ip, then it will fill the following file with the ip I want in the following command line: sshapss -p "password" ssh [email protected] for example, I have more or less the following idea, I need to fill the second file only with ip.

#!/bin/bash   
#Aki pega o que digitar e coloca na variavel sshpass

echo "IP DO ARQUIVO SSHPASS :"
read ip

# Aki ele nao faz nada + do que a saida do comando echo $ip ele coloca no arquivo sshpass.sh

echo $ip >> sshpass.sh
sed "sshpass -p "pdvlinux" "$ip sshpassh.sh

Answer 1

If I understood what you want to do. That would be, add a command in the IP-based sshpassh.sh file that has been reported. You do not need to add the IP and then give a sed to change the line.

Change the last two lines of your code to:

echo "sshpass -p \"senha\" ssh root@$ip" >> sshpassh.sh

If you always want to replace the command that was already defined in the file, switch from >> to >.

Tip: It wouldn’t be better to ssh with private/foreign key instead of sshpass?