Edit a file name using Python

Question

I am working with hundreds of pdf files, I have to rename them with the folder name where they are allocated.

for example:

pasta
  |--- pastajoão
           |-- celular.pdf
  |--- pastamaria
           |-- caderno.pdf

has how to use python to edit the name of the files leaving this way?:

pasta
  |--- pastajoão
           |-- pastajoão_celular.pdf
  |--- pastamaria
           |-- pastamaria_caderno.pdf

I have this code here:

    import pathlib import Path
    import os
    import shutil
    path = Path('meu caminho')
    for dirss in os.listdir(path=path):
    print(dirss)
    sleep(1)

    for dirs,  sub, files in os.walk(path):
        for file_ in files:
            path = os.path.join(dirs, file_)
            shutil.move(path, path)

    try:
        for _,  in path.glob('*.pdf'):
            edit = os.listdir()
            _.rename(edit)
    except Exception:
        print('Nenhum arquivo PDF')

he returns me this error

    for _,  in path.glob('*.pdf'):
    TypeError: cannot unpack non-iterable PosixPath object

also if I use the function rename() he was going to rename the entire file, right?

someone could help me ? :)

Answer 1

OPTION 1:

You can try something like:

import os
def change_file_name(sufix, path):
    for file in os.listdir(path):
        prefix = path.split("\\")[-1] + "_" #Armazena o nome da pasta atual
        if file.endswith(sufix) and not file.startswith(prefix):
            #Verifica se o arquivo tem o sufixo procurado e se o arquivo
            #não foi alterado anteriormente.
            os.rename(path + "\\" + file, path + "\\" + prefix + file)

    print(os.listdir(my_path))

sufix = ".pdf"
path = r"c:\my\choosed\path"

change_file_name(sufix, path)

Of course, then you can do your customization to suit the complexity of your system, but the basis to make a change would be +- this code above.

OPTION 2:

You play a 'father' folder and go mapping the files in the 'daughters' folders.

import os
def change_file_name(sufix, path):
    for files in os.walk(path):
        prefix = files[0].split("\\")[-1] + "_" #Armazena o nome da pasta atual

        for file in files[2]: #Passa arquivo por arquivo dentro da pasta
            if file.endswith(sufix) and not file.startswith(prefix):
                #Verifica se o arquivo tem o sufixo procurado e se o arquivo
                #não foi alterado anteriormente.
                os.rename(files[0] + "\\" + file, files[0] + "\\" + prefix + file)

        print(files,"\n")

sufix = ".pdf"
path = r"c:\my\choosed\parent\path"

change_file_name(sufix, path)

In this case, by your example

pasta
  |--- pastajoão
           |-- celular.pdf
  |--- pastamaria
           |-- caderno.pdf

You only need to pass the directory 'folder', because 'pastajoão' and 'pastamaria' would automatically pass in the function 'os.walk()', so you only pass the root directory (or parent) and the other directories will be mapped autonomously.

Answer 2

following your code I made this small modification

from pathlib import Path
import os

path = Path('diretorio')
try:
    for _ in path.glob('*.pdf'):
        new_name = os.path.basename(os.path.dirname(_))
        print(os.path.join(os.path.abspath(new_name), new_name))
        _.rename(f'{os.path.join(os.path.abspath(new_name), new_name)}_{os.path.basename(_)}')
except Exception as err:
    print(err)
    print('Nenhum arquivo PDF')

something I noticed that you’re using the import pathlib import Path and the right thing would be from pathlib import Path