Selenium Select Boot

Asked

Viewed 1,295 times

-2

Hello, running my python code can’t select a button

HTML:

<div class="pushpad_deny_button" style="position: relative;top:0;right:0;display: inline-block;float: left;width: 100px;margin-right: 6px;text-align: center;padding: 12px;text-align: center;font-weight: normal;font-size: 13px;color: #0670c3; cursor: pointer;">ALLOW</div>

My Code:

from selenium import webdriver

browser =webdriver.Chrome(r'')
al=browser.find_element_by_link_text('ALLOW')
al.click()

Error:selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector"

What I’m Doing Wrong?

python selenium

2 answers

6


The page is not loaded, the script does not wait alone the page has been downloaded and rendered, that is to say the DOM is probably not ready

For this you can apply a reasonable waiting time of 10 to 30 seconds limit, to wait for the DOM process, an example form implicit:

browser = webdriver.Chrome(r'')
browser.implicitly_wait(10)

If ten seconds isn’t enough use 20:

browser.implicitly_wait(20)

If you don’t use 30:

browser.implicitly_wait(30)

Or use the shape explicit, to add this at the top of the script:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

And change:

al=browser.find_element_by_link_text('ALLOW')

By (using Xpath):

al = WebDriverWait(browser, 10).until(
    EC.presence_of_element_located((By.XPATH, '//*[text() = "ALLOW"]'))
)

If ten seconds isn’t enough use 20:

WebDriverWait(browser, 20)

If you don’t use 30:

WebDriverWait(browser, 30)

You should only use more than this if you are sure the requested page is slow.

Checking if the element is clickable

Note that even if the element exists and is ready it may be that when using the click() it is "non-clickable" and will cause some problems like:

  • ElementNotVisibleException
  • ElementNotSelectableException

Depending on the situation, as hidden, then on buttons and links instead of EC.presence_of_element_located use EC.element_to_be_clickable, thus:

al = WebDriverWait(browser, 10).until(
    EC.element_to_be_clickable((By.XPATH, '//*[text() != "ALLOW"]'))
)

Note that for other types of elements you can apply other conditions (EC):

  • EC.title_is
  • EC.title_contains
  • EC.visibility_of_element_located
  • EC.visibility_of
  • EC.presence_of_all_elements_located
  • EC.text_to_be_present_in_element
  • EC.text_to_be_present_in_element_value
  • EC.frame_to_be_available_and_switch_to_it
  • EC.invisibility_of_element_located
  • EC.staleness_of
  • EC.element_to_be_selected
  • EC.element_located_to_be_selected
  • EC.element_selection_state_to_be
  • EC.element_located_selection_state_to_be
  • EC.alert_is_present

Do not use sleep()

It’s not that it shouldn’t, unless it’s in the interest of the actual script to use, but for DOM within Selenium the ideal is to use the WebDriverWait, this because it looks for the element at all times until the limit (10, 20, 30, etc.) ends, ie if find before the time limit it will not need to continue, it will process before and will not get stuck until the time runs out

  • 1

    Error:Attributeerror: module 'Selenium.webdriver.support.expected_conditions' has no attribute 'find_element_by_link_text'

  • 1

    @Pakito which version of Selenium? ps: I used this same code here and it worked, if not use implicity_wait ... DON’T USE THE sleep(), he does not "check" if the DOM is ready, will lock everything, the implicitly_wait, The GREAT advantage of implicitly_wait and Webdriverwait is that they search in the DOM until the time runs out, or if the element is found before the time limit it will proceed without having to finish the time, unlike the Sleep that just locks everything and will be forced to wait to finish all the time.

  • 1

    Gave another error:EC.presence_of_element_located((by.XPATH, '//*[text() != "ALLOW"]')) Nameerror: name 'by' is not defined

  • 1

    @Pakito import the from selenium.webdriver.common.by import By, sorry, there are many classes I often forget to mention: from Selenium.webdriver.common.by import By. I edited the answer

  • 1

    do not need al.click() ? in the 2 option?

  • Dear @Pakito never said this, I solved the part that was in your code, the part of "fetch the element", what you will do with it, click, remove, move, is of your interest... ps: the element_to_be_clickable "check if it is clickable", as described in the highlighted, do not click, just check if it is "possible", then you run click after what you want, in the examples solved the part with problem.

  • Only in the problem was the variable al.click()

  • @Pakito why? Not correct al= here: al = WebDriverWait(browser, 10).until(...?

  • No and that For when this variable also had the aim to click so I thought it was clear!

  • But Being Able to Help?

  • @Pakito didn’t understand, where exactly are you failing? Did you do this al = WebDriverWait(browser, 10).until(&#xA; EC.element_to_be_clickable((By.XPATH, '//*[text() != "ALLOW"]'))&#xA;) al.click()?

  • In the Code I Updated I just wanted to get Clickar in this Box.

Show 7 more comments

-1

from selenium import webdriver 
from time import sleep 

browser = webdriver.Chrome(r'').sleep(0.5)
al = browser.find_element_by_link_text('ALLOW')
al.click()

Follows a possible solution.

  • 1

    Solution: al = Webdriverwait(browser, 30). until( EC.element_to_be_clickable(((By.XPATH, '//*[text() = "NO THANKS"]')) ) al.click() solved!

Browser other questions tagged python selenium

You are not signed in. Login or sign up in order to post.