Encoding problem while extracting zip file - edited

Question

A webhook calls my API by sending a POST request. On the request body contains the url of a ZIP file.

Using the requests library, I perform a GET at the file url. I need to extract this few files from this zip and carry out a number of processes. The problem is that while trying to extract the file I come across the following error message: The following error occurs:

'ascii' codec can't encode character '\\xa2' in position 45: ordinal not in range(128)

Request code and attempt to extract the file:

import io
import requests
from zipfile import ZipFile

response = requests.get(url)

with ZipFile(io.BytesIO(response.content)) as thezip: # respose.content = arquivo zip em bytes por isso usei io.BytesIO()
    thezip.extractall()

When I print out the list of file names:

with ZipFile(io.BytesIO(response.content)) as thezip:
    print(thezip.namelist())

['Nao_Consistido/', 'Nao_Consistido/Relat\xc2\xa2rio de Previs\xc3\x86o de Vaz\xc3\x86o - Limite Inferior - LI.xls', 'Nao_Consistido/Relat\xc2\xa2rio de Previs\xc3\x86o de Vaz\xc3\x86o - Limite Superior - LS.xls', 'Nao_Consistido/Relat\xc2\xa2rio_de_Previs\xc3\x86o de Vaz\xc3\xa4es_PMO_de_DEZEMBRO_2019-preliminar.xls', 'Nao_Consistido/Todos_LI.prv', 'Nao_Consistido/Todos_LS.prv', 'Nao_Consistido/Todos_VE.prv']

I already set the PYTHONIOENCODING environment variable to utf-8 and it didn’t work. EDIT: After some tests I realized that the problem occurs only on the server (linux system), locally on Windows 10 does not occur.

Answer 1

One solution is to use Encode and Decode:

import io
import requests
from zipfile import ZipFile

response = requests.get(url)

for i in sys.argv[1:]:
    with ZipFile(io.BytesIO(response.content)) as thezip:
        for i in thezip.namelist():
                n = Path(i.encode('cp437').decode(encoding))
                if 1:
                    print(n)
                if i[-1] == '/':
                    if not n.exists():
                        n.mkdir()
                else:
                    with n.open('wb') as w:
                        w.write(thezip.read(i))

Answer 2

In python, as in other languages, interprets \ as a String escape, try to separate the path from the zip file with /.