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I’m new to messing with JS and it seems a silly mistake, but I caught it...
When I try to use the code as follows, it doesn’t work...
So it doesn’t work
<div id="intfloat" onclick="Showmenu()" class="intfloat">
<div id="intfloatM" class="intfloatM"></div>
<div id="intfloatN" class="intfloatN"></div>
<img class="ifimg" src="static/img/others/intfloat.png"/>
</div>
<script>
function Showmenu() {
var display = document.getElementById('intfloatM').style.display;
if(display == "none")
document.getElementById('intfloatN').style.display = 'block';
document.getElementById('intfloatM').style.display = 'block';
else
document.getElementById('intfloatM').style.display = 'none';
document.getElementById('intfloatN').style.display = 'none';
}
</script>
But if I only get one DIV it works
that’s how it works
function Showmenu() {
var display = document.getElementById('intfloatM').style.display;
if(display == "none")
document.getElementById('intfloatM').style.display = 'block';
else
document.getElementById('intfloatM').style.display = 'none';
}
Is there any restriction ? Or is something wrong ? ;-;
Dude, I don’t know exactly why you’re doing it this way, but wouldn’t you like to try the toggleClass? create an Hidden class and a show and then change the class with . toggleClass()?
– flourigh
The keys are missing in your if/Else, so only the first line of each block is really conditional, the second lines always run. And check whether
style.display == 'none'
will give problem the first time, because the value in this case will be''
. I suggest trying @flourigh’s suggestion.– bfavaretto
I understood, it was a silly mistake the lack of the keys "{}", with them worked normally, obg personal
– Vazafirst