Error in php url

Question

I have a querystring to work with url.

set_include_path('application' . PATH_SEPARATOR. get_include_path() );

            function getGet( $key ){
                    return isset( $_GET[ $key ] ) ? $_GET[ $key ] : null;
            }
                    $path = ('application');
                    $exe = getGet('exe');
                    if( is_file( ''.$path.'/'.$exe.'.php' ) )
                            include ''.$path.'/'.$exe.'.php';
                    else
                            include ''.$path.'/dash/404.php';

But I’m passing id for url, to generate new pages and I have a div hidden error so.

echo $exibir ? 'block' : 'none';

When I step into the url the error in this way:

if (!isset($_GET["error"]) == "error") {
    $exibir = null;
} else {
    $exibir = "block";
    //var_dump($nome);
}

So in return I have this:

 header('Location: '.$_SERVER['HTTP_REFERER'].'?error=error');

If you make a mistake, go to url error = error then mine query stays

?id=teste?error=error

But returns blank the screen and does not display the error message. When I do not pass the ID for url or create a IDin the link case, it works smoothly but within the query doesn’t work.

Answer 1

The first URL parameter has to be passed with ? (interrogation) the others are passed with & (and commercial).

Example:

www.algumacoisa.com.br/index.php? param1=4&param2=9&param3=999&param4=etc...

This if also has problem:

if (!isset($_GET["error"]) == "error") {
    $exibir = null;
} else {
    $exibir = "block";
    //var_dump($nome);
}

It should be something like this:

if (isset($_GET["error"]) && $_GET["error"] === "error") {
    $exibir = null;
} else {
    $exibir = "block";
    //var_dump($nome);
}