Printf does not show all variables

Question

I am studying C/C++ in college and came across the following problem, when I run the following code:

    #include <stdio.h>

    void main(){

    char name[10];
    int faltas;
    double media;

    printf("Digite seu nome, quantidade de faltas e sua media: \n");
    scanf("%s" "%d" "%.2f", &name, &faltas, &media);
    printf("Ola %s, voce tem %d faltas e sua media e %.2f",name,faltas,media);
}

Only the result does not show the mean value, as shown in the image below:

I wonder what I might be doing wrong, because in the exercise given by the teacher the resolution is the same as the code I put above.

Thanks in advance!!!

Answer 1

William,

Your scanf is incorrect, the double reading is done with lf, you also opened and closed the string more than once in the first parameter, the string reading (char array with %s) is not sent with & in front as it is an array.

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To fix, open only once the string of the first parameter, at the value %.2f, replace by lf, and when sending the name, do not use &, the result will be the following:

scanf("%s %d %lf", name, &faltas, &media);

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Your main function is with the void return, this even compiles, but it must be generating Warning, because normally the main returns an integer, int main(), you can return 0 only as test.

Answer 2

You used the "%f" float formatters instead of the double "lf" formatters in both the scanf and printf. Your string reading is also wrong since it is an array, I would use the gets command to read this specific string, clear the buffer and then read the other data from the program.