How do I get the angle of an image gradient, using Python and Opencv

Question

I need to get the angle of the gradient of an image, I’m programming in Python and using Google Colab for the codes.

I found this code here, which should show me the angle of the gradient:

import cv2
import numpy as np
import matplotlib.pyplot as plt
img = cv2.imread('./dt.jpg',0)
sobelx = cv2.Sobel(img,cv2.CV_32F,1,0,ksize=3)
sobely= cv2.Sobel(img,cv2.CV_32F,0,1,ksize=3)
phase=cv2.phase(sobelx,sobely,angleInDegrees=True)
print(phase)

but I also found this other code that should show me the angle:

gx = cv2.Sobel(img, cv2.CV_32F, 1, 0)
gy = cv2.Sobel(img, cv2.CV_32F, 0, 1)
print("\nX\n", gx, "\nY\n", gy)
mag, ang = cv2.cartToPolar(gx, gy)
print("\nMAG\n",mag,"\nANG\n",ang)

Both return me Arrays, but how do I convert this information to the degree of an angle? or is there another way to achieve this result?