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Hello, I am trying to read an XML file through a link and am not succeeding.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="utf-8">
</head>
<body>
<h1>Vagas de Trabalho</h1>
<?php
$link = "https://api.vulpi.com.br/media/feeds/linkedin.xml";
//link do arquivo xml
$xml = simplexml_load_file($link) -> source;
//carrega o arquivo XML e retornando um Array
foreach($xml -> job as $item){
echo "<strong>Empresa:</strong> "
.utf8_decode($item -> company)."<br />";
echo "<strong>Titulo:</strong> "
.utf8_decode($item -> title)."<br />";
echo "<strong>Descrição:</strong> "
.utf8_decode($item -> description)."<br />";
echo "<strong>Url:</strong> "
.utf8_decode($item -> applyUrl)."<br />";
echo "<strong>Lugar:</strong> "
.utf8_decode($item -> location)."<br />";
echo "<strong>Lugar:</strong> "
.utf8_decode($item -> salary)."<br />";
echo "<br />";
} //fim do foreach
?>
</body>
</html>
he error on line 17:
Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\xml\vulpi.php on line 16
I looked at some examples and I’m right.. Someone can help me.?
When parsing the XML element root does not enter the DOM, so there is no need to access
-> source
as he did.– Woss