Function to print directory on a Python Label

Question

I created a function that opens a file with Tkinter + filedialog, so far so good.

But I need to print the directory of the selected file on a label.

Follows function:

from tkinter import *
from tkinter import filedialog
import pandas as pd

def browse_button2():
    df2 = pd.read_csv(filedialog.askopenfile()) #aqui o botão seleciona o arquivo
    lb2["text"] = filedialog.askopenfilename() #aqui estou tentando definir que o label receba em sua propriedade "text" como valor a caminho do arquivo selecionado, Exemplo "C:\documentos\texte.csv"
    return df2

lb2 = Label(root, font=( 'arial', 10), bd=1, width=43, height=1, relief=RIDGE, borderwidth=1)
lb2.grid(row=2, column=0)
lb2.configure(background='#FFFFFF')
lb2.place(x=48, y=136)

Answer 1

To insert a text into Label use the method config and pass the directory obtained as argument for the parameter text. The Label object also works as a dictionary, so you can also set the key text of the object with the directory: Example:

label.config(text=path)
label["text"] = path

Your program is opening the dialog box twice because you are calling askopenfile() in the first line of the function and then you are calling askopenfilename() in the third row.

Maybe what you want is to use the directory of the selected file in filedialog.askopenfile() to insert into the label. To do this, just use the attribute name to get the file directory:

def browse_button2():
    file = filedialog.askopenfile() # Recebo o arquivo selecionado
    df2 = pd.read_csv(file)
    lb2["text"] = file.name # Estou passando o diretório do arquivo selecionado
    return df2