While with logical operator "or" - C++

Question

I’m having trouble finishing an algorithm.

When you insert a loop while In order not to allow an invalid form to be entered, the code shows an error in execution. If someone helps me by giving me some hint or solution, I am grateful.

Follows excerpt from the code:

printf("\n     DESEJA CONTINUAR O PROGRAMA?(YES ou NOT)== : ");                   
fflush(stdin);
gets(continuar);
strupr(continuar);
while((strcmp(continuar, "YES"!=0)) || (strcmp(continuar, "NOT"!=0))){
    printf("     \nDIGITE UMA FORMA VALIDA! (YES ou NOT)");                       
}       

Answer 1

Misparenting:

while((strcmp(continuar, "YES")!=0) || (strcmp(continuar, "NOT")!=0)){

and I believe that the OU in this case will not meet what you expect since if it is either "YES" or "NOT" will continue running the loop which does not seem to me to be what you want.

Since you say you are using C++ why don’t you use the class compare <string>?

while ((continuar.compare("YES") != 0) && (continuar.compare("NOT") != 0)) {