How to use the . replace() function in a list of lists or in a list of tuples?

Question

I am new in programming and new here on the site. I have a problem that I can not solve and luckily you exist. I’ve tried everything in my power and I’ve almost found the solution, only it was just about.

I have the following codes that I wrote with the help of answers here from the site:

A=[[3, 6, 3, 8, 9, 5, 5], [8, 6, 6, 4, 7, 10, 5, 3, 3, 3],[8, 6, 4, 5, 7, 3, 3, 2], [5, 4, 4, 10,3, 3, 0], [9, 6, 3, 6, 8, 8, 1]]

def chr_remove(antigo, remover):
    nova_string = antigo
    for x in remover:
        nova_string = nova_string.replace(x, '')
    return nova_string

remove1 = chr_remove(str(A), ",")

remove2 =chr_remove(remove1," ")

remove3 =remove2.replace("[","")

remove4 = remove3.replace("]",",")

remove_final = remove4.replace(",,","")

print(remove_final)

Code 2:

A=[(3, 6, 3, 8, 9, 5, 5), (8, 6, 6, 4, 7, 10, 5, 3, 3, 3), (8, 6, 4, 5, 7, 3, 3, 2), ( 5, 4, 4, 10,3, 3, 0), (9, 6, 3, 6, 8, 8, 1)]

def chr_remove(antigo, remover):
    nova_string = antigo
    for x in remover:
        nova_string = nova_string.replace(x, '')
    return nova_string

remove1 = chr_remove(str(A), ",")

remove2 =chr_remove(remove1," ")

remove3 =remove2.replace("(","")

remove4 = remove3.replace(")",",")

remove5 = remove4.replace("[","")

remove6 = remove5. replace(",]","")

remove_final= remove6.replace(",,","")

print(remove_final)

So far so good, the unwanted characters have been removed but the first problem appears when I read the items of the variable A and read the variable remove_final:

print(len(A))
>>>5

print(len(remove_final))
>>>46

And the second problem appears when I loop for the remove_final variable:

I’d like the result to come out like this:

73638955                                 
86647105333                              
86457332                                 
954410330                                
9636881

But the result comes out like this:

3                                        
6                                        
3                                        
8                                        
9                                        
5                                        
5                                       
,                                        
8                                        
6                                        
6                                        
4                                        
7                                        
1                                        
0
5
3
3
3
,
8
6
4
5
7
3
3
2
,
5
4
4
1
0
3
3
0
,
9
6
3
6
8
8
1

I tried to convert the string to list or tuple but nothing changes and if I ask to print as list or tuple the result also does not come as expected:

print(list(remove_final))
>>>['3', '6', '3', '8', '9', '5', '5', ',', '8', '6', '6', '4', '7', '1', '0', '5', '3', '3', '3', ',', '8', '6', '4', '5', '7', '3', '3', '2', ',', '5', '4', '4', '1', '0', '3', '3', '0', ',', '9', '6', '3', '6', '8', '8', '1']                     [Program finished]

print(tuple(remove_final))
>>>('3', '6', '3', '8', '9', '5', '5', ',', '8', '6', '6', '4', '7', '1', '0', '5', '3', '3', '3', ',', '8', '6', '4', '5', '7', '3', '3', '2', ',', '5', '4', '4', '1', '0', '3', '3', '0', ',', '9', '6', '3', '6', '8', '8', '1')                  [Program finished]

If I copy and paste the result in another editor I will be able to use normally as a tuple and be able to count the exact items and make a loop with the function .count() usually, only I have a few million data to analyze and there will be no printout, copy and paste in another editor.

Is there any module that has a function .replace() to list lists and list of tuples? Could someone help me solve this problem?

Answer 1

If I understand the goal, you want, from list, to iterate over all its elements, without comma. For this, just correct the line:

remove_final= remove6.replace(",,","")

for

remove_final= remove6.split(",")

This will return you a tuple with the values of concatenated sublists.

---

However, converting an iterable to a string, removing separators and delimiters from the string, and then working with the modified string is not the most appropriate way to iterate over lists and tuples, because it is difficult to understand by third parties and is inefficient, especially having a large data set.

The proper way to iterate over list lists depends on the structure that this data is

• Whether the algorithm will only iterate over list lists:

for sublista in A:
   texto = "".join([str(elemento) for elemento in sublista])
   print(texto)

• If it is not known how many levels of lists/tuples will be found, as in

A1 = [1, 5]
A2 = [[1,2],[5,6]]
A3 = [[[1,3],[1,2]],[[1,2],[5,6]]]

can do as follows

A1 = [1, 5]
A2 = [[1,2],[5,6]]
A3 = [[[1,3],[1,2]],[[1,2],[5,6]]]

def pegaValoresRecursivamente(entrada):
    #Testa se a entrada é lista ou tupla
    if type(entrada) in (list, tuple):
        for elemento in entrada:
            for elementoInterno in pegaValoresRecursivamente(elemento):
                yield elementoInterno
    else:
        yield entrada

print("A1")
for elem in pegaValoresRecursivamente(A1):
    print(elem)

print("\nA2")
for elem in pegaValoresRecursivamente(A2):
    print(elem)

print("\nA3")
for elem in pegaValoresRecursivamente(A3):
    print(elem)

A1
1
5

A2
1
2
5
6

A3
1
3
1
2
1
2
5
6

with the difference that in this case it will no longer print "line by line".