galley that part " if ((S%10=0) && (S<Vt))" is not going

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#include<stdio.h>
main()
{
char R[1];
int S, SQ, Nc, Vt;
   Nc=1000;
   Vt=10000;
   SQ=S/10; 
    while(R!="N" || Nc>0)
    {
    printf("limite:%d",Vt);
    printf("\nDigite quanto deseja sacar:");
    scanf("%d",&S);
    if ((S <0) || (S > Vt) || (S % 10 != 0))
    printf("Valor invalido");
    printf("Deseja realizar outro saque? [S/N]");
    scanf("%s",&R);
    if ((S%10=0) && (S<Vt))
    printf("%d nota(s) de 10.", SQ);
    printf("Deseja realizar outro saque? [S/N]");
    scanf("%s",&R);
    Vt=Vt-S;
    Nc=Nc-(S/10);
    if (Nc = 0)
    printf("Sem notas");
}
}
c

  • Isn’t one missing = in this comparison?

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  • correct the indentation of your code, to facilitate the understanding of other people

2 answers

1

In the language C you have to use 2 equal in comparison. In this case it would be: if (s%10 == 0 && s < vt)

0


You have to put another equal sign on that if, getting so if ((S%10==0) && (S<Vt))

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