Non-blocking execution with asynchronous Python functions

Question

I want a certain flow to continue even calling a async.sleep() in the code, I have the following code

import asyncio

async def funcao_1(name):
    print("entrando no sono...")
    await asyncio.sleep(3)
    print("saindo do sono...")

async def main():
    result = await asyncio.gather(funcao_1())


loop = asyncio.get_event_loop()

loop.run_until_complete(main())
print("rodando depois do run_until_complete")

Expected exit

entrando no sono...
rodando depois do run_until_complete
saindo do sono...

Return exit

entrando no sono...
saindo do sono...
rodando depois do run_until_complete

Python version

$ python3 --version
Python 3.6.7rc1

Is there any way to do this in Python?

Answer 1

To run two tasks concurrently, use the function async.gather.

Example:

import asyncio

async def funcao1():
    print('entrando no sono...')
    await asyncio.sleep(3)
    print('saindo do sono...')

async def funcao2():
    print('rodando de forma independente!')

async def main():
    await asyncio.gather(funcao1(), funcao2())

if __name__ == '__main__':
    # Se a versão do seu Python for menor que 3.7, use o seguinte:
    #
    # loop = asyncio.get_event_loop()
    # loop.run_until_complete(main())

    asyncio.run(main())

Terminal output:

entrando no sono...
rodando de forma independente!
saindo do sono...

Documentation: https://docs.python.org/3/library/asyncio-task.html#running-tasks-concurrently