declare(strict_types=1); display errors

Question

I’m starting to use language heavily typed in PHP 7.

declare(strict_types=1);    

But I couldn’t find a way to debug the bug and show where it is.

I searched hard but couldn’t find.

What should I wear?

I’ve tried to:

 ini_set("display_errors",true);
 ini_set("display_startup_erros",true);
 error_reporting( E_ALL | E_STRICT | E_NOTICE ); 

And I can’t display the mistakes of declare(strict_types=1);

The idea is, if I do:

public function verNumero (int $num) : int {
   return $num++;
}

and call the method so:

echo verNumero('7') 

instead of

echo verNumero(7)

This will bring me a mistake that without:

ini_set("display_errors",true);
ini_set("display_startup_erros",true);
error_reporting( E_ALL | E_STRICT | E_NOTICE ); 

it would not be possible to know where it is. On the contrary, the page would not even open.

What I want is to know what kind of error display controller to put in the code so I can see where the bug is instead of a blank page when using:

declare(strict_types=1); 

Answer 1

The syntax of the function ini_set() is wrong. Pay attention to the above comment to better understand the whole concept of what you want to do.

<?php
declare(strict_types = 1);
ini_set("display_errors", '1');
ini_set("display_startup_errors", '1');
error_reporting( E_ALL | E_STRICT | E_NOTICE ); 
function verNumero (int $num) : int {
   return $num++;
}
echo verNumero('7');
echo verNumero(7);

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.