Read two notes and display a string according to the average between them

Question

Make a program that receives two notes, calculate and show the average and the message that is in the following table:

0,0 - 4,0   Reprovado
4,0 - 7,0   Exame
7,0 - 10,0  Aprovado

print('ATIVIDADE 2 -ESTRUTURA CONDICIONAL')
print('----------------------------------')

nota_1 = float(input('Digite a primeira nota: '))
nota_2 = float(input('Digite a segunda nota: '))

média = (nota_1+nota_2)/2

print('A média aritmética é: ',média)

if float(média <=4.0):
    print('Reprovado')

elif float(média <=7.0):
    print('Exame')

elif float(média <=10.0):
    print('Aprovado')

Answer 1

I would risk something like:

media = (nota_1 + nota_2)/2
if media <= 4.0:
    print('reprovado')
elif media >= 7.0:
    print('aprovado')
else:
    print('exame')

Now, it’s not enough to know HOW, but yes WHAT this doing, first of all, avoid using accentuation as this can generate many problems by file formatting compatibility, this becomes even more dangerous in interpreted languages (as the case of Python).

Understanding the code: well, I did not put integer, but only the part that you doubt, note that I receive the values of the notes and do the average calculation, Python understands that the variable media is a float because she gets float as a value.

Understanding the conditional ones if, elif and else: they work with value boolean, that is to say, true or phony, do not compare different values from this, note that in media <= 4.0 the result of this comparison is a booleanalthough the data are float, That’s because the parole is comparing the condition <=, that is to say: "media is greater than or equal to 4.0, true or false?".

Notice that I set up a different structure, because understanding the problem of the table I see that the average being less than or equal to 4.0, the student is failed, if it is between 4.1 and 6.9 he enters the exam, but if it is above 7.0 he is approved.

Answer 2

Your code produces the expected output, as can be seen here: https://sopt-question-381571.acwoss.repl.run.

But there are considerations that will be important:

1. The initializing method of float, called on float(input('...')), throws an exception ValueError if the value returned by input cannot be represented as a floating point. This happens, for example, when a text is returned. It’s interesting you treat this in the code to give the feedback correct to the user and not break the application:

   while True:
       try:
           nota_1 = float(input('Entre com a nota 1:'))
           break
       except ValueError:
           print('Valor inválido! A nota precisa ser um número real')
   

2. There is no reason to consider negative marks in your code - because it would be strange for a student to get -5 on the test. Considering that the maximum note of the statement is 10.0, also has no reason to consider notes above that, so validating the range is also important:

   while True:
       try:
           nota_1 = float(input('Entre com a nota 1:'))
           if not 0 <= nota_1 <= 10:
               raise ValueError('Valor fora do intervalo')
           break
       except ValueError:
           print('Valor inválido! A nota precisa ser um número real entre 0 e 10.')
   

3. In the checks to display the result you made float(média <= 4). Notice that you put the entire comparison inside float. This works, but by mere "coincidence" as a consequence of the operator <= return a boolean and the boolean in Python is a subtype of the integer. So, if returned False, will be considered as 0.0, which will be interpreted as false by the structure if, similarly when returned True, will be considered 1.0, which will be interpreted as true. It would make more sense (read item 4) to do:

   if float(média) <= 4.0:
       ...
   elif float(média) <= 7.0:
       ...
   else:
       ...
   

4. The operator /, that will make the arithmetic division between the sum of the notes and the quantity, to calculate the average, already returns by default a floating point number. That is, to do média = (nota_1 + nota_2)/2 already makes it média be a float, then do float(média) is redundant.

5. You can generate strings repetitive through multiplication, with the operator *. For example, do '-' * 3 will generate the string '---'. This way, you don’t need to type all the characters like you did; and allied to this you can make the code more dynamic if you need to change the information:

   title = 'ATIVIDADE 2 -ESTRUTURA CONDICIONAL'
   
   print(title)
   print('-' * len(title))
   

Answer 3

Just to complement the answers, Serves for version 2 of python. following a different path if you are in need of using the accent in your work, course, college etc. You can use a syntax that allows the use by configuring the UTF-8 at the beginning of your code.

For example:

-*- coding: utf-8 -*-

According to python documentation, Unicode ( https://www.unicode.org/ ) is a specification that aims to list all characters used by human languages and give each character a unique code. Unicode specifications are continuously revised and updated to add new languages and symbols.