Why am I printing in this order?

Question

<?php
function foo($var){
 echo $var + 3;
}
$x = 1;

echo "foo($x) =".foo($x);
?>

I was watching some exercises in php,then I came across the code, thinking I was going to print foo(1) = 4, but printed 4foo(1) =.

Why am I calling the job foo($x) before the string of echo? He believed that the code would follow the normal 'stream' of the line and first print the string and only after that would call the function foo($x).

In my interpretation, where am I missing? Or php has some particularity?

Answer 1

You’re making a echo printing and not a return in function foo.

<?php
function foo($var){
 return $var + 3;
}
$x = 1;

echo "foo($x) =".foo($x);
?>