Ordering cards in Python

Question

I have a list of the cards and the suit of a deck that I need to sort. Considering the correct order: A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K And the suits: P(clubs). O(gold), E(sword), C(hearts) After reading the file with all the cards of all suits, I need to sort each suit. For example: reading the file returns (I will consider only a suit):

K P
A P
3 P 
9 P
10 P
J P
4 P
2 P
6 P
8 P
7 P
Q P
5 P

I need to sort by the value of the cards. I thought I’d play in a dictionary where the keys are the cards and the value is the suit, and then sort by the key, but I can’t get out of it. Can someone help me? My code so far:

arquivo = open('nome_arquivo.txt', 'r')
dados = arquivo.readlines()
dic = {}
for linha in dados:
    linha = linha.split()
    dic[linha[0]] = linha[1]
print(dic)

Answer 1

The "Sorted" method returns the sorted deck list in ascending order.

The "enumerate" method returns the index and the elements of the deck list.

Variables "k" and "v" receive the index and the list item deck.

The "strip" method removes line breaks, blank spaces, etc from the "string".

The "dic.update" method updates the dictionary, the key will be the variable "k" and "v" the value.

The "dic.get" method returns the value of a specified or empty key if the key does not exist.

arquivo = open('cartas.txt', 'r')
baralho = arquivo.readlines()

dic = {}

for k, v in enumerate(sorted(baralho)):    
    v = v.strip().strip('\n').strip('P')
    dic.update({k:v})

if dic.get(0) != 'A':
    dic.update({0:'A'})

if dic.get(9) != '10':
    dic.update({9:'10'})

if dic.get(11) != 'Q':
    dic.update({11:'Q'})

if dic.get(12) != 'K':
    dic.update({12:'K'})

print(dic)