Qpython 3 if/Elif/Else

Question

Why doesn’t Mey Qpython Android accept a simple if/Elif/Else condition? I’m using Python 3.

x = input('Select an option... ')
if x == 1:
    print('xxxx')
elif x == 2:
    print('yyyy')
elif x == 3:
    print('zzzz')
else:
    print('lalalalala')

(https://i.stack.Imgur.com/qlS40.jpg)

I’m sure everything is indented correctly, but still it always gives me the first elif as a syntax error, someone knows why?

Answer 1

The function input returns a string, and we if's you are comparing with numbers. So you can choose whether to compare with strings (by placing the numbers between quotes):

x = input('Select an option... ')
if x == '1':
    print('xxxx')
elif x == '2':
    print('yyyy')
elif x == '3':
    print('zzzz')
else:
    print('lalalalala')

Or becomes the result of input in a number, using int:

x = int(input('Select an option... '))
if x == 1:
    print('xxxx')
elif x == 2:
    print('yyyy')
elif x == 3:
    print('zzzz')
else:
    print('lalalalala')

Remembering that int can launch a ValueError if you don’t enter a number. Then you can use a while which, until a number is entered, keeps asking the user to type again:

while True:
    try:
        x = int(input('Select an option... '))
        break # número digitado, pode sair do while
    except ValueError:
        print('Você não digitou um número, tente novamente')

if x == 1:
    print('xxxx')
elif x == 2:
    print('yyyy')
elif x == 3:
    print('zzzz')
else:
    print('lalalalala')