-1
I have to invert a vector, example: ola = Alo.
#include<stdio.h>
#include<string.h>
#include<bits/stdc++.h>
int main()
{
char c[5];
scanf("%s" ,c);
for(int i=5; i>=-1;i--)
printf("%s" ,c[i]);
return 0;
}
1 answer
0
If you want to invert the array and not just write its inverted values you must create another variable. One way to do it is like this:
#include<stdio.h>
#include<string.h>
int main()
{
char c[10];
char invertida[10];
scanf("%s", c);
// strlen() retorna o tamanho da string
// for soma o j e percorre c invertido
int j = 0;
for(int i=strlen(c)-1; i>=0;i--) {
invertida[j] = c[i];
j += 1;
}
// Finaliza String
invertida[j] = '\0';
printf("%s", invertida);
return 0;
}
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You walk the string whole and exhibited herself
print("%s", c)every iteration. You should not display one character at a time?– Woss
print("%s", c[i]) tbm n works
– Guilherme Ioshua Belmont
Because
%sexpects a string and you are passing only one. Try to read and understand what each part of the code you are writing does.– Woss
printf("%c" ,c[i]); used %c it returns the correct result but before a "?"
– Guilherme Ioshua Belmont
return:12345 54321
– Guilherme Ioshua Belmont
but comes back with a special character similar to a translation
– Guilherme Ioshua Belmont
for(int i=strlen(c);i;)putchar(c[--i]);– pmg
Remember that in a string in C you need to predict the space for the terminator ' 0'. If you want to store 5 characters declare char c[6]; (indexes from 0 to 5). To print backwards: is (i=5; i>=0; i--) printf("%c", c[i]);
– anonimo