Python: Return of a specific function

Question

How can I access the function’s Return on_press(key)?

The program below captures keystrokes. Open, for example, the notepad and type test and teclhe Enter

The result in the list should be: lista = ['t','e','s','t','e','<key.esc>']

Can you give me a hint? Thanks.

from pynput import keyboard


def on_press(key):
    lista = []
    try:
        texto = '{0}'.format(key.char)
        lista.append(texto)
    except AttributeError:
        texto = '<{0}>'.format(key)
        lista.append(texto)
    return lista

def on_release(key):
    if key == keyboard.Key.esc:
        # Stop listener
        return False


# Collect events until released
with keyboard.Listener(
        on_press=on_press,
        on_release=on_release) as listener:
    listener.join()

Answer 1

You can either use a global variable or a class. Personally I prefer the idea of a class:

from pynput.keyboard import Key, Listener


class Keyload():
    def __init__(self):
        self.lista = []
        with Listener(
                on_press=self.on_press,
                on_release=self.on_release) as listener:
            listener.join()

    def on_press(self,key):
        print('{0} pressed'.format(key))
        self.lista.append('{0}'.format(key))

    def on_release(self,key):
        if key == Key.esc:
            # Stop listener
            return False

dados = Keyload()
print(dados.lista)

But if you still prefer to use a global variable:

from pynput.keyboard import Key, Listener

global lista

def on_press(key):
    print('{0} pressed'.format(key))
    lista.append('{0}'.format(key))

def on_release(key):
    if key == Key.esc:
        # Stop listener
        return False

# Collect events until released
lista = []
with Listener(
        on_press=on_press,
        on_release=on_release) as listener:
    listener.join()

print(lista)