1
In Python 3.7 items of a list can be arguments of a function?
def media(x,y,z): lista = [7,8,9]
1
In Python 3.7 items of a list can be arguments of a function?
def media(x,y,z): lista = [7,8,9]
2
Well, this code doesn’t seem to make much sense, but I imagine this is what you want:
def media(x, y, z):
return (x + y + z) // 3
lista = [7, 8, 9]
media(*lista)
Note that this particular example does not make much sense, the ideal in the case of average is to receive a list even and not a limited number of arguments. This would be a mistake:
print(media(*[8, 9]))
print(media(*[6, 7, 8, 9]))
This looks more like what you want:
def media(*lista):
soma = 0
for i in lista:
soma += i
return soma // len(lista)
lista = [7, 8, 9]
print(media(*lista))
Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.
Thank you very much!. It is part of an exercise that I am practicing. I put only a piece, which took away my sleep, to continue with others.
In the displayed code of the function the * usage for the list parameter can be omitted. If this is done, in the last line, when the media is printed, you should not use * either.
@Pa seems to me not to be true, I test and gave error.
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Possible duplicate of What is the meaning of the operator ( * ) asterisk?
– Woss