Problem passing argument via Python command line

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I am a beginner in Python and am facing the following problem to pass an argument via Python command line.

from math import pi
import sys


def circulo(r):
    return pi * float(r) ** 2


if __name__ == '__main__':
    r = sys.argv[1]
    area = circulo(r)
    print('Area do circulo ', area)

I’m having the following exit at the terminal:

Saida do Pycharm

python python-3.x

  • you have to put in place of 1 the value 0, since the first index is 0

  • 1

    I ran your code on my machine and had no problems. You are calling the file python by name alone? For right is right: $ python nome_arquivo.py args.

1 answer

2


Specifically in this case, the interpreter is understanding that the program is a shell script and not a program in Python. Add the shabang -- Be the #!/usr/bin/python or #!/usr/bin/env pythom -- at the beginning of the file for the program be correctly identified or call it through python argumentoLinComand.py.

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