Palindrome in C++

Question

The code below works, receives what was typed and stores it, only it does not make the logic to show whether it is palindromic or not and does not present on the screen the result for the user.

Please, where I went wrong and how to fix it?

#include <iostream>
using namespace std;

int main(void)
{

    string Texto = "";
    bool palindrono = true;
    int posicaoReversa = 0;

        cout << "Digite a palavra : " ;
        cin >> Texto;

    for (int i = Texto.length() -1; i > 0; i--)
    {

        posicaoReversa = Texto.length() - i - 1;

        if (Texto.substr(i, 1) != Texto.substr(posicaoReversa, 1))
        {
            palindrono = false;
            break;
        }
    }
}

Answer 1

All that was left was the presentation of the result, I only added a line at the end of the character check. I commented on some improvements you can make to your code and made them in example shown in ideone, especially consider cutting the time of the algorithm by half while avoiding comparing what has already been compared:

#include <iostream>
using namespace std;
int main(void) {
    string Texto = ""; //foi sempre usado camelcase, esta variável também deveria ser
    bool palindrono = true; //o nome da variável deveria ser palindromo
    int posicaoReversa = 0; //variável desnecessária
    cout << "Digite a palavra : ";
    cin >> Texto;
    //seria melhor pegar o tamanho do texto for do loop por questões de performance
    //também seria melhor comparar só até a metade, veja no ideone o exemplo modificado
    for (int i = Texto.length() - 1; i > 0; i--) {
        posicaoReversa = Texto.length() - i - 1; //não precisava colocar na variável
        //poderia usar o operador [] que já pega uma posição da string
        if (Texto.substr(i, 1) != Texto.substr(posicaoReversa, 1)) {
            palindrono = false;
            break;
        }
    }
    //terminou todo o processamento necessário, chegará aqui em duas situações:
    //1. ocorreu o break saindo do for e mandando para cá (não é palindromo)
    //2. terminou o loop do for e não tem mais o que repetir (é palindromo)
    cout << endl << (palindrono ? "É palindromo" : "Não é palindromo");
}

I did some code style enhancements and optimizations:

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

When you compare arara, For example, you only need to compare the last one with the first one and the second one with the second one. She originally performed three more unnecessary comparisons: she compared the middle one with herself, the second one with the penultimate one (which you had already compared) and the last one with the last one (which she had also compared). The code was not wrong, it could only be improved.