Problem after increment

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-1

Post-increment problem returning 67 and returning 7:

<?php 

$a = 10;
$b = 6;


echo ++$a; // pré incremento

echo "<br>";

echo $b++;

"<br>";

echo$b; // pós incremento

echo"<br>";



echo--$a;// pré decremento

 ?>
php echo
  • 1

    Comes out 67 only because the two values appear together. Note that you did not put the echo in the "<br>" between the values, which made PHP simply ignore the string. See https://repl.it/@acwoss/Cookednaturaltelephones.

  • For tag used previously you should read this: https://answall.com/q/101691/101

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1 answer

3

You probably just forgot to put one echo. So you must do what you wish:

$a = 10;
$b = 6;
echo ++$a; // pre incremento
echo "<br>";
echo $b++;
echo "<br>";
echo$b; // pós incremento
echo"<br>";
echo--$a;// pré decremento

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

In his code, he had 6 printed "<br>" loose that disappears in the result and then has printed the 7, as there is nothing separating them is 67.

  • that was really thank you

  • @Gabrielflor see on [tour] the best way to say thank you.

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