How to check if the seat is free and if you are not asking the user to type again by inserting an 'X' in the occupied space?

Question

I need the user to enter where he wants to sit by informing the row and column he wants, if the user chooses the position 0-1 the program will register and write to a txt file later mind that information, and will enter a looping to register a new user, where he will type what position he wants and if he type a position where it is already occupied by another user the program will not accept putting a X in place to demonstrate that it is occupied.

Follows the code...

#include<stdio.h>
#include <stdlib.h>

void main()
{
    printf("\n \nEscolha seu assento: \n\n");

    int m, n, fileira, assento;
    int lugares[10][16];

    for(m=1;m<10;m++){
        for(n=1;n<16;n++){
            printf("[%d- %d]", m, n);
        }

        printf("\n");   
    }

    printf("\nFileira desejada: ");
    scanf("%d",&fileira);
    printf("Assento desejado: ");
    scanf("%d",&assento);

    system("pause");
}

Answer 1

I guess it’s almost over by then. Just add this code already done in a while and create a boolean control variable to terminate the loop. I don’t know if I understand how you’ll manage the seats, but I’ll assume it’s 0 for vacant and 1 for busy. In your case then add:

lugares[m][n] = 0;

Then make the loop:

bool encerrar = false;

while (!encerrar)
{
    //seu código sem as declarações das váriaveis.

    if (lugares[fileira][assento] == 1)
        printf("Posicao Ocupada!\n");
    else
        lugares[fileira][assento] = 1;
}

I think there’s a good start to moving on..