Problem with excess Decimals!

Question

Initially I was developing a python code that would help me better understand Nikola Tesla’s number theory(video).

Explaining quickly, starting with 360, adding each separate value results in 9, for example :3 + 6 + 0 = 9 , always dividing the value 360 by 2 , adding up the separate numbers always results in 9, for example: 360/2= 180, 1+8+0 = 9 180/2 = 90 9+0 = 9 And so on

Initially the base code I made was this in python

real_valor=360 ; string_valor=str(real_valor); valor_unitario=[]; soma_unitaria=0
for i in string_valor:
    if i == '.':
        continue
valor_unitario.append(int(i))
print(valor_unitario)
for g in valor_unitario:
    soma_unitaria += g
print(soma_unitaria)

Using the first as a basis, concludes this one :

soma_unitaria=0; from time import sleep
while True:
    sleep(0.5)
    if soma_unitaria == 0:
        real_valor = 360; string_valor = str(real_valor); valor_unitario = []
    else:
        string_valor='';soma_unitaria = 0; real_valor /= 2; string_valor = (str(real_valor)); valor_unitario.clear()
    for numero in string_valor:
        if numero == '.':
            continue
        valor_unitario.append(int(numero))
    for valor in valor_unitario:
        soma_unitaria += valor
    print("Valor Inicial : {}\nSoma dos valores unitarios divido : {}\n".format(real_valor, soma_unitaria))

The code Works initially. The problem starts after many decimal places, I can’t convert the value floats assign to float or int number (the values are initially string so I can separate them one by one and add them together)

Line error 11

How can I solve this problem, many decimal places end up adding the value and , which in strings I cannot convert to numbers?

Answer 1

There is a difference between Python2 and Python3 that leads to this error:

With Python2, for example, int(str(5/2)) provides 2. With Python3, the same happens to you: Valueerror: invalid literal for int() based 10: '2.5'

If you need to convert some string that can contain float instead of int, you can use the following formula :

int (float (myStr))

How float ('3.0') and float ('3') provide 3.0, but int ('3.0') gives the error.