String vector condition error in C

Question

I’m having a hard time with a specific exercise:

#include <stdio.h>
#include <stdlib.h>
#include <locale.h>
#include <windows.h>
#include <ctype.h>
#include <string.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
    setlocale(LC_ALL, "portuguese");

    char nome[0][50], hoje[0][50];

    printf("Digite o nome do local: ");

    scanf("%s", &nome[0]);

    printf("Digite o dia: ");

    scanf("%s", &hoje[0]);
    toupper((char)hoje);

    if((hoje[0] == "SEGUNDA") && (strlen(nome) < 100)){
        printf("Nome é: %s\n", nome[0]);
        printf("Hoje é: SEGUNDA\n");
    }else if((hoje[0] == "TERÇA") && (strlen(nome) < 100)){
        printf("Nome é: %s\n", nome[0]);
        printf("Hoje é: TERÇA\n");
    }else{
        printf("Dia da semana nao é SEGUNDA e nem TERÇA");
    }

    system("pause >> null");
    return 0;
}

when compiled, it does not consider if and pause the program after inputs and reversing the condition if(!(hoje[0] == "SEGUNDA") && (strlen(nome) < 100)) with the ! he printa, but goes out for ex: Seu nome é: SEGUNDA, Hoje é: SEGUNDA it replaces the name variable for today when it prints the output, what can it be ? the address or allocation ? Thank you.