How to use regular expressions?

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I have a string with this value:

Romania","PROXY_IP":"93.118.243.19","PROXY_LAST_UPDATE Indonesia","PROXY_IP":"117.102.88.121","PROXY_LAST_UPDATE Russia","PROXY_IP":"194.135.97.178","PROXY_LAST_UPDATE Malaysia,"PROXY_IP":"192.228.193.78","PROXY_LAST_UPDATE

and find all parts with " "PROXY_IP":"XXX.XX.XXX.XXX" " Code I tried to:

static Regex ipR = new Regex(@""PROXY_IP":"\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}"");

but everything turned red... I don’t know how to make Regex search for quotes in the middle of the string too

c# regex expressions
  • 1

    Take a look at this link https://answall.com/questions/172741/como-indica-numa-regex-que-os-s%C3%Admbolos-e-os-par%C3%Aanteses-s%C3%A3o-uma-das-al in the quote-escaping example, I think it will help you a lot

  • @Luizaugusto thanks for the reply, but it did not help much since expressions in java is different than in c#

  • I don’t program much in C# but I believe the problem is in the quotes same. As for the IP, I think we can "simplify" to \d{1,3}(\.\d{1,3}){3} - don’t forget to escape the point too, because . means "any character", while \. means "point". Of course you can complicate even more if you want a regex that only accepts numbers between zero and 255

  • Another link, http://aurelio.net/regex/c/ is the complete material of the Aurelio.

  • I don’t know how you define the best answer, but thank you @hkotsubo

1 answer

2


To use quotation marks on a Regex, you need to use the backslash ( ). I mean, your regex would look like this:

(\"PROXY_IP\":\"\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}\")

There are some very good teaching regex sites that are interactive. Take a look at Regexr, created an example using your case.

  • 1

    Yes, I studied a little and understood the "logic of regex" haha Thank you! The doubt has been resolved

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