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On the screen in normal mode use at the click of a button directing the screen to a div at the top:
$('html,body').animate({scrollTop:$('.backTop').offset().top}, 150);
But, taking the screen on Full Screen how to make this function work?
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On the screen in normal mode use at the click of a button directing the screen to a div at the top:
$('html,body').animate({scrollTop:$('.backTop').offset().top}, 150);
But, taking the screen on Full Screen how to make this function work?
1
To solve your problem just replace the code:
$('html,body').animate({scrollTop:$('.backTop').offset().top}, 150);
for this $('#leitor').animate({scrollTop:$('.leitor_top').offset().top}, 150);
For who stands in full screen is the div called "reader". I hope I’ve helped!
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Test this:
var suaDiv = document.getElementById("leitor");
suaDiv.scrollTop = 0;
jewelry? Tested and unsuccessful yet
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Solved,
Simply by using:
$('html,body').animate({scrollTop:$('.backTop').offset().top}, 150);
was assigning to the body scroll, but should be assigning to the div scroll that is in fullscreen, getting:
$('#leitor').animate({
scrollTop: $(".backTop").offset().top
}, 150);
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You have an answer here you will take a look at it: https://answall.com/questions/1855/existe-alguma-maneira-de-ativar-a-tela-cheia-do-navegador-javascript
– LeAndrade
Good boss, but, my fullscreen is already working, my problem is sending the user to a div at the top of the page when this screen is fullscreen
– sNniffer
But what would be the difficulty then sNniffer?
– LeAndrade
It doesn’t work here
$('html,body').animate({scrollTop:$('.backTop').offset().top}, 150);
fullscreen– sNniffer