(Python) Find words with total vowels being even

Question

I’d like to ask for your help. I have a code in Python where a part is missing: parse the words of a sentence and save the ones that have an even number of vowels.

Example: "I came home and went to play video games". The word "I arrived" has 4 vowels, 4 is even so I need to keep it in a list.

I want to do this with all the sentences read and then rewrite them inside the list.

Incomplete code:

def frases():
vog="aeiou"
dig="0123456789"
sd=0
sv=0
vp=[]

f = str(input('Digite uma frase: ')).lower()

while f != '':
    vp = f.split()

    for a in range(len(vp)):
        for l in vp[a]:
            if l in vog:
                sv+=1

        for d in vp[a]:
            if d in dig:
                sd += 1

    print('Palavras contidas na frase: {}'.format(len(vp)))
    print('Total de vogais: {}'.format(sv))
    print('Total de dígitos: {}'.format(sd))
    print()

        f = str(input('Digite uma frase: ')).lower()


frases()

Answer 1

See if that helps you.

def frases():
    vog="aeiou"
    dig="0123456789"
    sd=0
    sv=0
    vp=[]
    matriz_palavras_vogais_pares = []

    f = str(input('Digite uma frase: ')).lower()

    while f != '':

        palavras_vogais_pares = []
        vogais_na_frase = 0
        digitos_na_frase = 0

        vp = f.split()

        for palavra in vp:
            vogais = 0
            digitos = 0
            for letra in palavra:
                if letra in vog:
                    vogais += 1
                if letra in dig:
                    digitos += 1

            vogais_na_frase += vogais
            digitos_na_frase += digitos

            sv += vogais
            sd += digitos

            if vogais %2 == 0: #Ou ainda if (vogais %2 == 0) and (palavra not in palavras_vogais_pares):
                palavras_vogais_pares.append(palavra)

        matriz_palavras_vogais_pares.append(palavras_vogais_pares)

        print('Palavras contidas na frase: {}'.format(len(vp)))
        print('Total de vogais nessa frase: {}'.format(vogais_na_frase))
        print('Total de dígitos nessa frase: {}'.format(digitos_na_frase))
        print('Total de vogais: {}'.format(sv))
        print('Total de dígitos: {}'.format(sd))
        print('Palavras com número par de vogais: {}'.format(palavras_vogais_pares))
        print('Todas as palavras: {}'.format(matriz_palavras_vogais_pares))
        print()


        f = str(input('Digite uma frase: ')).lower()

Answer 2

Regex is usually a very useful tool for this sort of thing. As there is already an answer that follows the structure of your code here goes one using only regex and considering only vowels and consonants present in English.

import re
    f = '.'
    while f != '':
        f = str(input('Digite uma frase ou pressione enter para sair: ')).lower()
        print('Palavras contidas na frase: {}'.format(len(re.findall(r'\b\w+\b',f))))
        v_br=r'[aáãâàéeiíoóõúu]'
        c_br=r'[b-dçf-hj-np-tv-z]'
        v2_br = r'(\b(?:'+c_br+r'*'+v_br+c_br+r'*'+v_br+c_br+r'*)+\b)'
        rv = re.compile(v_br, re.UNICODE)
        r2v = re.compile(v2_br, re.UNICODE)
        p2v = re.findall(r2v,f)
        print('Total de vogais nessa frase: {}'.format(len(re.findall(v_br,f))))
        print('Total de dígitos nessa frase: {}'.format(len(re.findall(r'\d',f))))
        print('Palavras com número par de vogais: {}'.format(str(len(p2v))+", "+str(p2v)))

Answer 3

Updated but incomplete code:

def frases():
vog="aáãâàéeiíoóõúu"
dig="0123456789"
sd=0
sv=0
vp=[]
vtp=[]
vtv=[]
vtd=[]
vpp=[]

f = str(input('Digite uma frase ou pressione enter para terminar: ')).lower()
vp = f.split()
vtp.append(len(vp))

for p in vp:
    v = 0
    d = 0
    for l in p:
        if l in vog:
            v += 1
        if l in dig:
            d += 1
    sv += v
    sd += d

vtv.append(sv)
vtd.append(sd)
v=0
d=0
sv=0
sd=0

while f != '':
    f = str(input('Digite uma frase ou pressione enter para terminar: ')).lower()
    vp = f.split()
    vtp.append(len(vp))

    for p in vp:
        v = 0
        d = 0
        for l in p:
            if l in vog:
                v += 1
            if l in dig:
                d += 1
        sv += v
        sd += d

    vtv.append(sv)
    vtd.append(sd)
    v=0
    d=0
    sv=0
    sd=0

for i in range(len(vtp)-1):
    print()
    print('Palavras contidas na {}º frase: {}'.format(i+1, vtp[i]))
    print('Total de vogais na {}º frase: {}'.format(i+1, vtv[i]))
    print('Total de dígitos na {}º: {}'.format(i+1, vtd[i]))
    print()

phrases()

I need to work on that part:

if v %2 == 0 and v != 0 and p not in vpp:
 vpp.append(p)
if len(vpp) > 0:
for i in range(len(vpp)-1):
    print('Palavras com número par de vogais da {}º frase: {}'.format(i+1, vpp[i]))

I would need a list for each sentence. Example: list1 = words with even vowels of the first sentence. Lista2 = words with even vowels of the second sentence. etc....