Regular Expression | Picking part of content between 2 markers

Question

I have no knowledge of regular expression, so I do not know if it is possible to carry out the solution of my problem.

Throughout the HTML code of a site, it always has a code similar to this.

"placeholder":"https:\/\/ci.hdv6.com\/videos\/78\/13\/8787575\/thumbs_65\/(m=eaAaGwObaaaweyaY)(mh=c_sPzVwXUfENWpYI)6.jpg",

I’d like to do the following.

Grab all the content that starts at:

"placeholder":"

And ends in:

",

In case it would be:

https:\/\/ci.hdv6.com\/videos\/78\/13\/8787575\/thumbs_65\/(m=eaAaGwObaaaweyaY)(mh=c_sPzVwXUfENWpYI)6.jpg

NOTE: I’m using CURL to get all the HTML of a site, so I can find a Techo like this to get just this link.

And extremely important to get through the word PLACEHOLDER as an initial marker, as there are other similar links on the site.

Answer 1

let string = "placeholder:https:\/\/ci.hdv6.com\/videos\/78\/13\/8787575\/thumbs_65\/(m=eaAaGwObaaaweyaY)(mh=c_sPzVwXUfENWpYI)6.jpg"

let result = /https.+jpg$/.exec(string)[0]

console.log(result);