"fimenquanto sem enquanto correspondente" error

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algoritmo "semnome"
var
   n,i,ma,me:inteiro
inicio
   i<-0
   me<-0
   ma<-0
   enquanto (i<21) faca
      Escreval ("insira um numero inteiro:")
      leia (n)
      se n<0 entao
         me<- me+1
      senao
         se n>0 entao
            ma<-ma+1
         fimse
         i<-i+1
      fimenquanto
      escreval ("a quantidade de numeros maiores inseridos foi:",ma)
      escreval ("e a quantidade de numeros menores inseridos foi:",me)
fimalgoritmo
visualg

1 answer

1


In your code, you have two se and only one fimse. Was missing the fimse to the first se. Your code should be like this:

algoritmo "semnome"
var
   n,i,ma,me:inteiro
inicio
   i<-0
   me<-0
   ma<-0
   enquanto (i<21) faca
      Escreval ("insira um numero inteiro:")
      leia (n)
      se n<0 entao
         me<- me+1
      senao
         se n>0 entao
            ma<-ma+1
         fimse
      fimse
      i<-i+1
   fimenquanto
   escreval ("a quantidade de numeros maiores inseridos foi:",ma)
   escreval ("e a quantidade de numeros menores inseridos foi:",me)
fimalgoritmo

The reason the error message refers to fimenquanto there was a block se opened, and therefore the expected would be a fimse. However, the compiler found a fimenquanto, that wasn’t what he expected.

  • got it, thanks

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