Number of pages in php page

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I have a page in PHP where I did the paging that is working perfectly, but I noticed that the screen is getting full of links with the numbering of the pages.

Currently I present only 3 results to each page. They would help me to limit the number of links of pagination?

I tried to do this limit, but always the page increases a number to +. I already managed to limit at the beginning, when I move to the next page the number of links increases to infinity!

Follows the code:

<?php
}
//PAGINAÇAO
if ($registros_ > 3) {
//Verificar a pagina anterior e posterior

	
	$max_links = 8;
	
	$links_laterais = ceil($max_links / 2);
	
	$pagina_anterior = $pagina - $links_laterais;
    $pagina_posterior = $pagina + $links_laterais;
	
    print "<div class='container'>
<div>
				<ul class='pagination'>
					<li>";
    if ($pagina_anterior > 0) {
        print "<a href='pesquisas.php?pagina=$pagina_anterior&tipo=$tipo&seletor=$seletor&filtro=$filtro' aria-label='Previous'>
                                <span aria-hidden='true'>&laquo;</span>
                            </a>";
    } else {
        print "<span aria-hidden='true'>&laquo;</span>";
    }
    print "</li>";
//Apresentar a paginacao

    for ($i = $pagina_anterior; $i < $pagina_posterior; $i++) {
	    if ($i >=1){ 
        print"<li><a href='pesquisas.php?pagina=$i&tipo=$tipo&seletor=$seletor&filtro=$filtro'>$i</a></li>";
    }
	}
	
    print "<li>";
    if ($pagina_posterior <= $num_pagina) {
        print " <a href='pesquisas.php?pagina=$pagina_posterior&tipo=$tipo&seletor=$seletor&filtro=$filtro' aria-label='Previous'>
            <span aria-hidden='true''>&raquo;</span>
        </a>";
    } else {
        print "<span aria-hidden='true'>&raquo;</span>";
    }
    print "</div></div>";
}
//F

I managed to solve my problem! Follow the code for those who have the same difficulty.

<?php
}
//PAGINAÇAO
if ($registros_ > 3) {
//Verificar a pagina anterior e posterior

	
	$max_links = 6;
	
	$links_laterais = ceil($max_links / 3);
	
	$pagina_anterior = $pagina - $links_laterais;
    $pagina_posterior = $pagina + $links_laterais;
	
    print "<div class='container'>
<div>
				<ul class='pagination'>
					<li>";
    if ($pagina_anterior > 0) {
        print "<a href='pesquisas.php?pagina=$pagina_anterior&tipo=$tipo&seletor=$seletor&filtro=$filtro' aria-label='Previous'>
                                <span aria-hidden='true'>&laquo;</span>
                            </a>";
    } else {
        print "<span aria-hidden='true'>&laquo;</span>";
    }
    print "</li>";
//Apresentar a paginacao

    for ($i = $pagina_anterior; $i < $pagina_posterior; $i++) {
	    if (($i >=1) && ($i <= $num_pagina)){ 
        print"<li><a href='pesquisas.php?pagina=$i&tipo=$tipo&seletor=$seletor&filtro=$filtro'>$i</a></li>";
    }
	}
	
    print "<li>";
    if ($pagina_posterior <= $num_pagina) {
        print " <a href='pesquisas.php?pagina=$pagina_posterior&tipo=$tipo&seletor=$seletor&filtro=$filtro' aria-label='Previous'>
            <span aria-hidden='true''>&raquo;</span>
        </a>";
    } else {
        print "<span aria-hidden='true'>&raquo;</span>";
    }
    print "</div></div>";
}
//FIM PAGINAÇAO
?>

php twitter-bootstrap

  • You are opening many *tags, but you are not closing them. $num_pagina is getting what value?

  • Opa amigo, $quantidade_pg = 3; / $num_pagina = Ceil($registros_/$quantidade_pg);

  • Ever tried to replace $limite + 1 for $limite? Ps.: Avoid using the Snippet, it does not work with PHP.

  • I’ve tried it and it didn’t work it always goes beyond

  • Put the solution you found as an answer and then you can accept it

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