What is wrong in the double variable

Question

I need to make an algorithm that the user informs two values and return the biggest among them using double, but when compiling it from the error pointing something in double but do not know how to solve, someone can help me and explain how I would use correctly?

#include <stdio.h>
double maior(double *x, double *y)    
{  
    double maior;   

    if (*x>*y)
    {
        maior=*x;
        return maior;
    }

    else
    {
        maior=*y;
    }

    return maior;
}



int main()  
{   

    double x,y,m;

    printf("Informe dois valores com espaco entre eles:");
    scanf("%f %f",&x,&y);

    m=maior(&x,&y);

    printf("O maior eh: %f \n",m);


    return 0;
}

Answer 1

The problem that is happening is due to the fact that you are trying to return a variable of type double in a role that supposedly should return a int. To return the double, change the function return type to double:

double maior(double *x, double *y) {  
    double m;   

    if (*x>*y)
    {
        m=*x;
        return m;
    }

    else
    {
        m=*y;
    }

    return m;
}

printf("O maior é: %f\n", m); // Faltou o formatador

Just adding, its function could be reduced to the following code:

double maior(double x, double y) {
    if(x < y)
        return y;
    return x;
}