0
Good actually I got in brute force wanted to know, there is another way to do my code mathematically
#include <stdio.h>
#include <string.h>
int main(int argc, char** argv)
{
char numero[1000],aux[10000];
scanf("%s", numero);
for(int i = 0; i < numero[i] && numero[i] != '\0'; i++)
{
if(numero[i] == '0')
{
strcat(aux,"0000");
}
else if(numero[i] == '1')
{
strcat(aux,"0001");
}
else if(numero[i] == '2')
{
strcat(aux,"0010");
}
else if(numero[i] == '3')
{
strcat(aux,"0011");
}
else if(numero[i] == '4')
{
strcat(aux,"0100");
}
else if(numero[i] == '5')
{
strcat(aux,"0101");
}
else if(numero[i] == '6')
{
strcat(aux,"0110");
}
else if(numero[i] == '7')
{
strcat(aux,"0111");
}
else if(numero[i] == '8')
{
strcat(aux,"1000");
}
else if(numero[i] == '9')
{
strcat(aux,"1001");
}
else if((numero[i] == 'A')||(numero[i])=='a')
{
strcat(aux,"1010");
}
else if((numero[i] == 'B')||(numero[i])=='b')
{
strcat(aux,"1011");
}
else if((numero[i] == 'C')||(numero[i])=='c')
{
strcat(aux,"1100");
}
else if((numero[i] == 'D')||(numero[i])=='d')
{
strcat(aux,"1101");
}
else if((numero[i] == 'E')||(numero[i])=='e')
{
strcat(aux,"1110");
}
else if((numero[i] == 'F')||(numero[i])=='f')
{
strcat(aux,"1111");
}
}
puts(aux);
return 0;
}
Forgive my ignorance, but I didn’t understand some things in your code.. why the loop is, why the arrays have so much space. In my view there are 2 problems in your code: 1 - the loop is broken if any of the numbers is different from ' 0', the ideal would not be a continue? and another problem is, instead of using Else if, use switch case.
– M. Bertolazo
You could declare a
int int_var;and then usescanf('%x', &int_var), this way you can already convert from hexa directly to an integer.– lemoce