php arrays + function

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Good,

I have a doubt..

I’m using error system[] in array. I created a function that simply shows the design of the error + message

 warning_alert('Caracteres do tituto superiores a 4.');

 function warning_alert($text) {
  echo "
  <div class='alert warning'>
  <span class='closebtn'>&times;</span>  
  <strong><i class='fas fa-exclamation-circle'></i></strong> $text
  </div>"; 
 }

This is where it says the ERROR message. But it’s not working...

 $errors[] = warning_alert('Caracteres do tituto superiores a 4.');

This is the error message :

 if(strlen($ads_title) < 4 && strlen($ads_title) > 35) {

  $errors[] = warning_alert('Caracteres do tituto superiores a 4.'); 

 }

Array errors works this way. 

          if(!empty($errors)) {  

              echo display_errors($errors);

          } else {

             if(move_uploaded_file($file_tmp, $file_destination)) {}

Any idea?

php

  • show error where??? what are you doing that does not show error?

  • not... This way does not give... $errors[] = warning_alert('Title characters greater than 4.'); It is as if no errors are heard...

  • Understand, I explained right up to... the $Errors[] array is where it shows all the errors of each check... but I want to show the error as I did, because WARNING_ALERT is a function with "ECHO $mensamgem"

  • I’ve edited, see now if you understand!

  • first, if you don’t need to store in an array! second inside a function you should return with Return and outside call echo warning_alert(""); then your code isn’t working because there are conceptual errors !!!

  • Can you correct me?... so I learn..

  • But.. I still need $errors [] = because it’s part of the system, and I can’t use ECHO

  • why? you need the $erros[]? that is not in your question the main reason! , is a confusing question!

  • I already edited, see the ERROR message!

  • with your code only this works (even having problems) if(strlen($ads_title) < 4 && strlen($ads_title) > 35) {&#xA; warning_alert('Caracteres do tituto superiores a 4.'); &#xA;}

  • Understand... I have to use $errors[] because it validates in another check. There is no way to Use Array $errors + function?????????????

  • Switch echo to Return in its function. I don’t know what the function that displays the data looks like, maybe you need to move it too.

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Hello!!

Try to use the return instead of echo, because you want it to store in the array, but the function is no return.

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