2
Good evening. I am unable to find the error. I intend to build a list as I enter the date in the input date. Below is html:
<div class="form-group">
<label for="data_aula">Turma</label>
<div >
<select class="form-control" name="turma" id="turma">
<option></option>
<option value="Iniciante">Iniciante</option>
<option value="Avançado">Avançado</option>
</select>
</div>
</div>
<div class="form-group">
<label for="data_aula">Informe a Data de Aula</label>
<input class="form-control" id="data_aula" name="data_aula" type="date" placeholder="dd/mm/aaaa" required="required" />
</div>
Then below is the table that must be filled:
<form name="form1" class="form-horizontal" method="POST" action="processa/proc_notas_geral.php">
<div class="row">
<div class="col-md-6">
<table class="table table-striped table-hover table-condensed" id="tabela">
<thead>
<th>Foto</th>
<th>Nome</th>
<th>Marcar</th>
</thead>
<tbody>
<!--aqui quero montar minha tabela -->
</tbody>
</table>
<div class="form-group">
<button type="submit" class="btn btn-success" id="sendListaAluno">Enviar Notas</button>
</div>
</div>
</div>
Now below the code to perform ajax:
<script type="text/javascript">
$(document).ready(function(){
$('#data_aula').change(function() {
var data_aula = $('#data_aula').val();
var turma = $('#turma').val();
if(turma.length == 0){
alert("A turma não foi selecionada ainda.");
return;
}
$.ajax({
type : 'post',
dataType: 'json',
url : 'processa/proc_lista_alunos_presentes.php',
data : {data_aula: data_aula, turma : turma},
success: function (dados) {
linha = "";
if (dados == ""){
alert ("Não retornou nada!");
return;
}
for (i = 0; i < dados.length; i++) {
var caminho_foto = dados[i].imagem==""? "imagens/sem_imagem.png" : "fotos/" + dados[i].imagem;
linha += "<td hidden='true'>" + dados[i].id + "</td>";
linha += "<td><img src=" + caminho_foto + " width='60' height='60' name='foto_aluno' class='img-circle img-responsive'></td>";
linha += "<td style='text-align: left'>" + dados[i].nome + "</td>";
linha += "<td style='text-align: center'> <input type='checkbox' class='form-check-input' value=" + dados[i].id + "</td>";
$('#tabela tbody').html(linha);
}
}
});
})
})
And in php contains the return as follows:
<?php
session_start();
include_once("../seguranca.php");
include_once("../conexao.php");
$data_aula = $_POST['data_aula'];
$turma = $_POST['turma'];
$query_somente_alunos_presentes="SELECT
a.id_membro as id,
a.nome, a.imagem
FROM
MEMBROS a, FREQUENCIA c
where A.id_tipo_membro=2 AND
C.id_membro = A.id_membro AND
C.data_aula = '$data_aula' AND
A.turma ='$turma'
ORDER BY nome;";
$sql = mysqli_query($conn,$query_somente_alunos_presentes);
$linhas=mysqli_num_rows($sql);
if( $linhas > 0 ) {
while($resultado = mysqli_fetch_assoc($qryLista)){
$vetor[] = array_map('utf8_encode', $resultado);
}
//Passando vetor em forma de json
echo json_encode($vetor);
}
?>
I do not know if there are any errors in the ajax parameters, or in my php return. It does not return anything, and when I go to the browser console does not point errors!
I inserted a.log console as the main one guided here, and the output came out as follows:
(2) [{…}, {…}]
0
:
{id: "42", nome: "Antonio cesar paulo", imagem: "Antonio_1521556093.jpg"}
1
:
{id: "35", nome: "Artur Souza Oliveira", imagem: ""}
length
:
2
__proto__
:
Array(0)
I opened the Chrome developer tool went to the console. My table was not filled.
I inserted in my question the output I got in return ajax.
– PauloGalego
This $qryList variable that is in php code, picked it from somewhere else.. was it... Thank you very much!!!
– PauloGalego
@Paulogalego formulate an answer with what you have done or changed.
– Don't Panic
OK, do it now!
– PauloGalego