Google Drive API to search only images

Question

I recently started to study the Google Drive API. I am able to list all the files in Drive and I have access to all its attributes. However, I was asked to search only for the image files.

What did I do? I played the search code inside a Javascript:

if(file.extension === 'jpg' || file.extension === 'png')

But there it is. My search is analyzing all the files from the drive and listing only the . jpg and . png, making my search very poorly optimized. I wonder if anyone could help me. I want my search to search through Drive and return only the img extension files.

Follow the API link https://developers.google.com/drive/v3/web/quickstart/js . From now on, thank you.

Answer 1

Since I don’t know what your code is, I’ll leave a snippet of how you can do it.

As I said in my comment, just add the property q and use one of the operators below followed by the amount you want.

Operators:

• contains The contents of one string are present in the other.
• = The contents of a string or boolean are the same as the other.
• != The contents of a string or boolean are not the same as the other.
• < The value is less than another.
• <= The value is less than or equal to another.
• > The reverse valve larger than another.
• >= The value is greater than or equal to another.
• in An element within a collection.
• and Returns items that match both clauses.
• or Returns items that match any clause.
• not Denies a search clause.
• has A collection contains an element that matches the parameters.

How to do:

"q": "<campo>" <operador> "<valor"> ["<campo>" <operador> "<valor"> ],

Example:

function listFiles() {
    gapi.client.drive.files.list({
        'pageSize': 10,
        'q': "mimeType contains 'image/jpeg' or mimeType contains 'image/png'",
        'fields': "nextPageToken, files(id, name)"
    }).then(function(response) {
        console.log('Files:');
        let files = response.result.files;

        if (files && files.length > 0) {
            for (let i = 0; i < files.length; i++) {
                let file = files[i];

                console.log(file.name + ' (' + file.id + ')');
            }
        } else {
            console.log('No files found.');
        }
    });
}