Can anyone help me with this?

Question

5) Make a program that receives the basic salary of an employee, calculate and show your salary to receive, knowing that the employee has bonus of R $ 50 and pays tax 10%

#include <stdio.h>
int main()

{
float sal,imposto,s_final;
printf(" CALCULO DE SALARIO \n \n");

printf("Digite seu salario: ");
scanf("%f",&sal);

imposto= sal/100 * 0.1;
s_final = sal-imposto+50;

printf("Salario a receber: %f reais \n",&s_final);
printf("Valor dos impostos: %f reais",&sal);
return 0;
}

Answer 1

Hello was viewing your code and the logic is correct, however, you forgot that the "&" is only used for scanf and not for printf (if you use for print will take the address of the memory and not the content).

I’ve reworked the code:

 #include <stdio.h>
 int main()
 {
 float sal,imposto,s_final;
 printf(" CALCULO DE SALARIO \n \n");
 printf("Digite seu salario: ");
 scanf("%f",&sal);

 imposto= (sal*10)/100;
 s_final = sal-imposto+50;

 printf("Salario a receber: %f reais \n",s_final);
 printf("Valor dos impostos: %f reais",sal);

 } 

I hope you helped him!

Answer 2

& (and commercial) is used to pass the address of a variable, i.e., when you do : printf("Salary receivable: %f real n",&s_final); printf("Value of taxes: %f real",&salt);

the printf function is waiting for a float, because in the string it has "%f", but "&s_final" represents the address that the value of the variable "s_final" is stored.

To fix this, simply remove & in calls from printf function.