How to declare a javascript array that will receive a JSON array

Question

How to declare a javascript array that will receive a JSON array

Asked 6 years, 9 months ago

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0

Given the interface:

export interface Pergunta {
    id: number
    titulo: string
    opcoes:[]
}

I want the options array to receive its options array:

{
    "id": "1",
    "titulo": "Qual o seu comportamento em relação aos seus investimentos?",
    "opcoes": [
      {
        "description": "Preservar meu dinheiro sem correr risco"
      },
      {
        "description": "Ganhar mais dinheiro, assumindo riscos moderados"
      },
      {
        "description": "Ganhar mais dinheiro, assumindo riscos agressivo"
      }
    ]
  },

2 answers

2

export interface Pergunta {
    id: number;
    titulo: string;
    opcoes: Opcao[];
}

export interface Opcao {
    description: string;
}

This would be the most correct way to receive your data

Yes, you are declaring a numeric value as String.... @Marcus Dacorréggio is correct.

– Ramos

2018/03/13 at 19:55
Marcus pq a public opcoes: Array<Typodeopcoes>; would be wrong?

– Tiago Tiede

2018/03/13 at 19:55
@How I call this array options in question array *ngfor ?

– ttlelis_12

2018/03/13 at 19:59
If you are using Angular 2+ you can call using *ngFor="let opcao of pergunta.opcoes"

– Marcus Hert da Coregio

2018/03/13 at 20:01
Type <Section class="content"> <div class="Row"> <div *ngFor="Let question of questions" class="col-Sm-6 col-Xs-12"> <app-question [question]="></app-question> </div> </div> </Section>

– ttlelis_12

2018/03/13 at 20:01
Inside of your Component app-pergunta you will probably have the app-pergunta-opcao or something, in which you will use *ngFor I passed above

– Marcus Hert da Coregio

2018/03/13 at 20:03
@Tiagotiede I believe that for Angular to make the object deserialize the Array would not serve, would have to be TipoDeOpcoes[]

– Marcus Hert da Coregio

2018/03/13 at 20:05
I understand. The strange thing that I made a pocket and it was without stress here. Well the important thing is to learn and help the friend :D

– Tiago Tiede

2018/03/13 at 20:34

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by Tiago Tiede • **186** points · Answer 1 · 2018-03-13T19:35:10+00:00

I believe the best solution is for you to type the attribute array options. In some cases when you don’t do this process, you can use a array of any. For example:

public opcoes: Array<any>;

However I believe that the best solution to your problem would be something like this:

export interface Pergunta {
    public id: number
    public titulo: string;
    public opcoes: Array<TipoDeOpcoes>;   } 

    export interface TipoDeOpcoes {
            public description: string   
}