Conflict of forms

Question

I have 2 forms, one by ajax and the other php normal. both forms are working, but when I run the php form without ajax it returns me the errors of the php form with ajax.

PHP Com ajax

if ($_SERVER["REQUEST_METHOD"] == "POST") {

PHP Sem ajax

if (isset($_POST['Btnlk'])){

If the conflict is not there I put all the code.

Form code with ajax

<form class="form1"  method="POST" enctype="multipart/form-data">

    <div id="ressult_log_succes"></div>
    <div id="ressult_log_error"></div>

    <p>E-mail</p>
    <input type="text" name="Email_user" placeholder="Informe seu E-mail">

    <p>Senha</p>
    <input type="password" name="Senha_user" placeholder="Informe a sua senha">

    <input type="submit" id="Bot_login" name="Logar_sn" value="Logar">
</form>

<script>
    $(function(){
        $(".form1").submit(function(event){
            event.preventDefault();
            var formDados = $(".form1").serialize();

            $.ajax({
                url:"/complement-of-archive/ConsultaLoginUser.php",
                type:"POST",
                data:formDados,
                cache:false,
                processData:false,
                success:function(data){
                    $("#ressult_log_succes").html(data);
                },
                error:function(data){
                    $("#ressult_log_error").html(data);
                },
                dataType:"html"
            });
            return false;
        });
    });
</script>

My form without ajax

<form class="form2" method="POST" enctype="multipart/form-data">
    <input type="hidden" name="ID_Pagina_LK_DL" value="2">
    <input type="text" name="Usuario_LK_DL" value="" placeholder="Informe seu nome">
    <input type="submit" name="Btnlk" value="1">
</form>

<?php
    require_once('SysLKDLe.php');
?>

php from my form without ajax

<?php
    if (isset($_POST['Btnlk']) && $_POST['Btnlk'] == "1") {
        $LK_DL = 1;
        $ID_Pagina_LK_DL = $_POST['ID_Pagina_LK_DL'];
        $ID_Usuario_LK_DL = $_POST['Usuario_LK_DL'];

        if ($LK_DL != 1) {
        }
        else{
            $SQL_LK_DL = mysqli_query($conex,"INSERT INTO Banco_lk (LK_DL, Nome_LK_DL, IDUser_LK_DL) VALUES ('$LK_DL', '$ID_Pagina_LK_DL', '$ID_Usuario_LK_DL')");
        }
    }
?>

Answer 1

If both forms are sending data via POST, when making such a verification if ($_SERVER["REQUEST_METHOD"] == "POST") the two forms enter, put another condition to the if(), for example

Form 1:

<form action="meuphp.php" method="post">
    <!-- ... -->
    <input type="submit" name="botao_enviar" value="Cadastrar">
</form>

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST" && isset($_POST["botao_enviar"]) && $_POST["botao_enviar"] == "Cadastrar") {

Form 2:

<form action="meuphp.php" method="post">
    <!-- ... -->
    <input type="submit" name="botao_enviar" value="Alterar">
</form>

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST" && isset($_POST["botao_enviar"]) && $_POST["botao_enviar"] == "Alterar") {

You must compare different values or names in both forms, it can be the upload button or fields you have in one form but not in another

Another option is to pass a variable op via GET for example:

<form action="meuphp.php?op=cadastrar" method="post">
    <!-- ... -->
    <input type="submit" name="botao_enviar" value="Cadastrar">
</form>

<form action="meuphp.php?op=alterar" method="post">
    <!-- ... -->
    <input type="submit" name="botao_enviar" value="Cadastrar">
</form>

<?php
if ($_GET["op"] == "cadastrar") {
    //...
} else if ($_GET["op"] == "alterar") {
    //...
}

Can also do with switch case prefer