Pick up part of a URL with PHP Explode

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1

How do I take only what is after ? and before &?

$url = "https://www.dominio.com/login?erro=1&data=2018-03-06";
$url_cod = explode('?', $url);

There he is returning everything that comes after the question mark.

php

  • To the URL, ?erro=1&data=2018-03-06 or ?data=2018-03-06&erro=1 are the same thing, so what value should you take? And why do you need to do this?

  • I need to get only error=1, is that I am doing a validation via GET on a page.

  • But it is the URL of the page itself or any URL as in the example?

  • From the page itself. I said wrong, via GET will not work, because I need it to return with the word error, exactly like this: error=1

3 answers

2

If you want to take the parameters passed by GET from any URL - not necessarily the current page, which PHP already makes available in $_GET - there are specific functions for this:

  1. parse_url receives a URL and returns array with the main components - including querystring, which is what matters here.

  2. parse_str is made to break querystrings in array.

Bringing the two together:

$url = "https://www.dominio.com/login?erro=1&data=2018-03-06";
$partes = parse_url($url);
if(!empty($partes['query'])) {
    $vars = [];
    parse_str($partes['query'], $vars);
    var_dump($vars);
}

// Saída:
//
// array(2) {
//   ["erro"]=>
//   string(1) "1"
//   ["data"]=>
//   string(10) "2018-03-06"
// }

See it working on Ideone.

About the approach you were trying:

How do I catch only what is after ? and before &?

Thinking about this problem in a generic way (because to treat Urls I would use the code above), it is simple to solve with string manipulation. With the explode you already managed to get a string like this:

$sua_string = "erro=1&data=2018-03-06";

Looking at that, just find the first & and take everything before him:

$sua_string = "erro=1&data=2018-03-06";
$pos = strpos($sua_string, '&');
$resultado = substr($sua_string, 0, $pos-1);
echo $resultado; // erro=1

1

Anything that comes after ? is populated by the super global $_GET, so, if you want to take some parameter in the url you can do as follows:

$data = $_GET['data'];

This code would return the value '2018-03-06'.

To catch the mistake just do:

$erro = $_GET['erro'];

This code would return the value 1.

Since you want the value with the variable name, you can concatenate the value with a string.

$erroString = 'erro='.$erro;

  • I need it to return only the value: error=1

  • I edited it. You can get any value from the url, just pass the corresponding key

  • Not only do I need the value, I need it to return with the word error too.

  • Only you concatenate the value obtained with the string you want. I edited the answer doing this.

0

The explode will turn $url_cod into an array, to pick up what is before just put:

$parte_url = $url_cod[1];
//Ou [0] para oque vem antes

For the '&' you use the same system

Or if you want to get the GET parameters, do as @Phelipe answered above

 $url = "www.google.com?&nome_da_variavel_recebida=123";
 $valor = $_GET['nome_da_variavel_recebida'];
 //Nesse caso $valor seria igual a 123

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