Javascript does not have a native function to perform this process.
However, you can use this function to return an extended number:
//+ Carlos R. L. Rodrigues
//@ http://jsfromhell.com/string/extenso [rev. #3]
String.prototype.extenso = function(c){
var ex = [
["zero", "um", "dois", "três", "quatro", "cinco", "seis", "sete", "oito", "nove", "dez", "onze", "doze", "treze", "quatorze", "quinze", "dezesseis", "dezessete", "dezoito", "dezenove"],
["dez", "vinte", "trinta", "quarenta", "cinqüenta", "sessenta", "setenta", "oitenta", "noventa"],
["cem", "cento", "duzentos", "trezentos", "quatrocentos", "quinhentos", "seiscentos", "setecentos", "oitocentos", "novecentos"],
["mil", "milhão", "bilhão", "trilhão", "quadrilhão", "quintilhão", "sextilhão", "setilhão", "octilhão", "nonilhão", "decilhão", "undecilhão", "dodecilhão", "tredecilhão", "quatrodecilhão", "quindecilhão", "sedecilhão", "septendecilhão", "octencilhão", "nonencilhão"]
];
var a, n, v, i, n = this.replace(c ? /[^,\d]/g : /\D/g, "").split(","), e = " e ", $ = "real", d = "centavo", sl;
for(var f = n.length - 1, l, j = -1, r = [], s = [], t = ""; ++j <= f; s = []){
j && (n[j] = (("." + n[j]) * 1).toFixed(2).slice(2));
if(!(a = (v = n[j]).slice((l = v.length) % 3).match(/\d{3}/g), v = l % 3 ? [v.slice(0, l % 3)] : [], v = a ? v.concat(a) : v).length) continue;
for(a = -1, l = v.length; ++a < l; t = ""){
if(!(i = v[a] * 1)) continue;
i % 100 < 20 && (t += ex[0][i % 100]) ||
i % 100 + 1 && (t += ex[1][(i % 100 / 10 >> 0) - 1] + (i % 10 ? e + ex[0][i % 10] : ""));
s.push((i < 100 ? t : !(i % 100) ? ex[2][i == 100 ? 0 : i / 100 >> 0] : (ex[2][i / 100 >> 0] + e + t)) +
((t = l - a - 2) > -1 ? " " + (i > 1 && t > 0 ? ex[3][t].replace("ão", "ões") : ex[3][t]) : ""));
}
a = ((sl = s.length) > 1 ? (a = s.pop(), s.join(" ") + e + a) : s.join("") || ((!j && (n[j + 1] * 1 > 0) || r.length) ? "" : ex[0][0]));
a && r.push(a + (c ? (" " + (v.join("") * 1 > 1 ? j ? d + "s" : (/0{6,}$/.test(n[0]) ? "de " : "") + $.replace("l", "is") : j ? d : $)) : ""));
}
return r.join(e);
}
She uses String.prototype
so adds a method applied to all strings. For example:
"123".extenso();
How to use it you can see here
Reference:
Jsfromhell
response of: link
here is a package in npm: https://www.npmjs.com/package/extenso
– Alex
boy... I saw something like that a long time ago, see if that’s it: http://jsfromhell.com/pt/string/extenso
– Leandro RR
the @Marcelorafael solution is better! :)
– Leandro RR
@Marcelorafael, this npm package solves my problem, thank you so much for pointing him out to me, and I thank the others for their help and collaboration...
– LeonardoEbert