Test equal values (data) in PHP

Question

Hello, I need to test if two dates are equal in PHP (current date x last working day of the month), the two are strings, but I’m not getting the result using the following code:

 if(strcmp($ultimo, $hoje) == 0)
     echo "<br><br>As duas datas são iguais";
 else
     echo "<br><br>As duas datas são diferentes"; 

The calculation for the last working day is as follows::

 $mes = 07;
 $ano = 2014;
 $dias = cal_days_in_month(CAL_GREGORIAN, $mes, $ano);
 $ultimo = mktime(0, 0, 0, $mes, $dias, $ano); 
 $dia = date("j", $ultimo);
 $dia_semana = date("w", $ultimo);
 if($dia_semana == 0){
   $dia--;
   $dia--;
 }
 if($dia_semana == 6)
   $dia--;
 $ultimo = (string)mktime(0, 0, 0, $mes, $dia, $ano);

For the current date:

$hoje= date("d/m/Y"); 

The two dates show the result 31/07/2014, but I’m not getting equality in the result. If anyone can help.

Answer 1

Using date()

<?php
 date_default_timezone_set('America/Sao_Paulo');
 $mes = 07;
 $ano = 2014;
 $dias = cal_days_in_month(CAL_GREGORIAN, $mes, $ano);
 $ultimo = mktime(0, 0, 0, $mes, $dias, $ano); 
 $dia = date("j", $ultimo);
 $dia_semana = date("w", $ultimo);
 if($dia_semana == 0){
   $dia--;
   $dia--;
 }
 if($dia_semana == 6)
   $dia--;
 //repare que precisa-se de converter o mktime para date()
 $ultimo = date("d/m/Y",mktime(0, 0, 0, $mes, $dia, $ano));
 $hoje= date("d/m/Y"); 
 if ($ultimo==$hoje)
     echo "verdadeiro";
 else
     echo "falso";

For PHP versions 5.2 or later

Datetime:

$timezone = new DateTimeZone('America/Edmonton');
 //...
$ultimo = DateTime::createFromFormat('j-M-Y', '$dia-$mes-$ano',$timezone);
$hoje=  new DateTime(null, $timezone);
if ($ultimo==$hoje)
    echo "verdadeiro";
else
    echo "falso";

Answer 2

You can use the strtotime function to generate an integer and then compare, see:

$dateIni   =   '01/08/2014';

$dateFim   =   '30/08/2014';

echo strtotime($dateIni)  ==  strtotime($dateFim) ? true : false;

Answer 3

Convert the dates to strtotime() and make the comparison, comparison in whole numbers becomes easier.