C Counter Bug - Syntax Problem

Question

Guys, I was doing some basic programming exercises and I came across a bug that I didn’t quite understand:

#include <stdio.h>
#include <stdlib.h>


//Program prints the odd numbers until a determined limit. 
int main()
{
    int numeric_limits;
    int count = 1;

    printf("Enter the limit number.\n");
    scanf(" %d", &numeric_limits);

    while(count <= numeric_limits)
    {
        printf(" %d\n", count);
        count+2;
    }

    return 0;
}

This code above is in an infinite loop "Uns". While this one below works perfectly:

#include <stdio.h>
#include <stdlib.h>


//Program prints the odd numbers until a determined limit. 
int main()
{
    int numeric_limits;
    int count = 1;

    printf("Enter the limit number.\n");
    scanf(" %d", &numeric_limits);

    while(count <= numeric_limits)
    {
        printf(" %d\n", count);
        count++;
        count++;
    }

    return 0;
}

I’m coding in codeblocks... I went to test it on some online compiler to see if it was a compiler problem, but the online compiler gave it an infinite loop too... Does anyone know why this happens?

Answer 1

count+2;

I think you meant it:

count += 2;

I mean, you forgot about =.