Regex in Python to find several possible names

Question

I need to find the name of the judge in a file of labor process, but first I need to know if he is Judge(a), Rapporteur(a), Judge(a) Rapporteur(a) or Judge(a).

I’m using the following Regex:

f_regex = re.compile(r'ju(iz|íza) relato(r|a) | ju(iz|íza) | relato(r|a) | desembargado(r|ra)')

But it’s not working.

EDIT:

Problem solved. The problem was not in the regex but within a function of mine. Sorry for the inconvenience, I also did not know what was happening. Thanks to all who have gone out of their time to help me, truly.

Answer 1

Guys, a lot of the problems were because of the spaces.

Folder with some txts: https://drive.google.com/drive/folders/1aqUjO4x3cvmKFYJJZJKV8dMmDxGGBOqq?usp=sharing

The following function picks up much (judge, rapporteur, judge), but is not getting judge rapporteur. Maybe the problem is in the masculino|feminino:

def find_juiz(file):
file_lines = list(reversed(line_tokenize(file)))[:10]
file_chunked = str(file_lines)
name_juiz = ''
search = re.search(r'ju(iz|íza)\s*relato(r|ra)|ju(iz|íza)|relato(r|ra)|desembargado(r|ra)',file_chunked)
if search is not None:
    for i,line in enumerate(file_lines):
        if line.strip() in search.group():
            # while file_lines[i+1] is not None:
            #     j=i
            #     name_juiz += file_lines[j+1]
            #     j+=1
            # return name_juiz
            return i,line.strip()
else:
    return

ps: that line_tokenize comes from the package nltk(Natural Language Tool Kit), which is a package to work with NLP (Natural Language Processing) in Python. It takes a text and separates it into a list of lines, where each position is a line. Since it’s a pattern that the judges' names are at the end I reversed that list with reversed and picked up the last (which are now the first) 10 lines (list(reversed(line_tokenize(file)))[:10])

Answer 2

Following the text published in the question comment: http://m.uploadedit.com/bbtc/1513873742547.txt

You can capture this information with regex \b(.+)(?:\n.*)(?:relatora?|desembargadora?|ju[íi]za?)

Explanation:

\b(.+) => Here we capture a pattern at the beginning. How we define .+, it will pick up all the content until the line break. (Item below)

(?:\n.*) => Here we inform the algorithm to capture all the code of the next line.

(?:rapporteur?| chief judge?| ju[íi]za?) => Here we filter a few words. We add a ? to inform that the word prior to it is optional.

?: => This option we use to prevent these data from being captured, we want this group to be only validated.

Regex in operation

Answer 3

First problem:

your regex will not work with .match, he demands that you marry completely string with its regex.

Second problem:

Another thing, your file .txt may be in UTF-8 and so he might not recognize the accents, so if he’s using urllib (chance read the files remotely) on read() (of urllib) from Handler add the .decode('utf-8')

If your document is in ASCII or windows-1252 or iso-8859-1 on open() add the parameter encoding:

See the examples at the end of the answer

Third problem:

Your regex is searching for anything that contains spaces before and after, remember sentences can end in scores like ., !, ?, etc and can also be separated by ,, ;, :, or even be isolated by quotation marks "

Your regex should be something like:

r'(\s|^)(ju(iz|íza) relato(r|a)|ju(iz|íza)|relato(r|a)|desembargado(r|ra))[!?",;:.\s]'

• The \s at the beginning indicates that it can contain space, line break or tab
• The [!?",;:.\s] indicates that there may be scores at the end of the word and the \s indicates that can spaces spaces, line break or tab at the end of the word.

---

Example if downloading from a URL

If you are reading from the URL do so:

# -*- coding: utf-8 -*-

import re             # importa modulo
import urllib.request # importa modulo

url = "http://m.uploadedit.com/bbtc/1513873742547.txt"
parttern = r'(\s|^)(ju(iz|íza) relato(r|a)|ju(iz|íza)|relato(r|a)|desembargado(r|ra))[!?",;:.\s]'

with urllib.request.urlopen(url) as f:
    data = f.read().decode('utf-8')

    p = re.compile(parttern)
    resultado = p.search(data)

    print(resultado)

If the file remote is in windows-1252 or iso-8859-1 use so:

data = f.read().decode('latin1')

Example if reading a file on the machine

If the file .txt is in utf-8 use encoding='utf-8', if it’s windows-1252 or iso-8859-1 use encoding='latin1'

import re

arquivo = 'foobar.txt'
parttern = r'(\s|^)(ju(iz|íza) relato(r|a)|ju(iz|íza)|relato(r|a)|desembargado(r|ra))[!?",;:.\s]'

with open(arquivo, encoding='utf-8') as f:
    data = f.read()

    p = re.compile(parttern)
    resultado = p.search(data)

    print(resultado)

Answer 4

Hello, I created a version below with small changes in your regex:

import re

f_regex = re.compile(r'^(\b|.+\s)ju(iz|íza) |^(\b|.+\s)relato(r|a) |^(\b|.+\s)desembargado(r|ra) ', re.IGNORECASE)


success = ["juíza Fulana", "Juiz Fulano", "desembargador Fulano", "Desembargadora Fulana", "Sr. Juiz de Tal"]
fail = ["Fulana de Tal", "Fulano de Tal", "Fulano de Tal", "Juízane Fulana de Tal", "Juizo de Tal", "Dajuiz de Tal"]

print("\nDeve encontrar:")
for string in success:
    result = f_regex.match(string)
    print(string,'- encontrou?',result!=None)

print("\nNao deve encontrar:")
for string in fail:
    result = f_regex.match(string)
    print(string,'- encontrou?',result!=None)

I created some strings to test as well. I hope it helps.